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lesantik [10]
3 years ago
7

Determine whether each statement describes a solution of a strong electrolyte, weak electrolyte, or non-electrolyte.

Chemistry
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

Please find the terms with their correct description in the explanation section.

Explanation:

An electrolyte is a substance that dissociates or ionizes into cations (positive charged ions) and anions (negative charged ions) in an aqueous solution. An electrolyte can either be strong or weak depending on how well it ionizes and its level of conductivity. However, a non-electrolyte neither ionizes in a solution nor conducts electricity.

Based on this;

1. Weak electrolyte: Has a medium level of conductivity i.e. partially conducts electricity

2. Strong electrolyte: Contains a complete solute

3. Non-electrolyte: Has little or no conductivity i.e. cannot conduct electricity because it doesn't dissociate into ions.

4. Strong electrolyte: Has the highest conductivity i.e. conducts electricity very well.

5. Strong electrolyte: Contains a completely dissociated solute i.e. the solute of the electrolyte separates into anions and cations completely.

6. Weak electrolyte: Contains a partially dissociated solute i.e. the ions of the solute do not ionize completely in the solution.

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How many grams of silver chromate will precipitate when 150. mL of 0.500 M silver nitrate are added to 100. mL of 0.400 M potass
sergiy2304 [10]

The amount of silver chromate that precipitates after addition of solutions is 12.44 g.

Number of moles:

The number of moles is the product of molarity of the solution and its volume. The formula is expressed as:

Moles = Molarity x Volume

Calculations:

Step 1:

The molecular formula of silver nitrate is AgNO3. The number of moles of silver nitrate is calculated as:

Moles of AgNO3 = 0.500 M x (150/1000) L

= 0.075 mol

Step 2:

The molecular formula potassium chromate is K2CrO4. The number of moles of potassium chromate is calculated as:

Moles of K2CrO4 = 0.400 M x (100/1000) L

= 0.04 mol

Step 3:

The balanced chemical reaction between AgNO3 and K2CrO4 is:

2AgNO3 + K2CrO4 -----> Ag2CrO4 + 2KNO3

The required number of moles of K2CrO4 = 0.075 mol/2 = 0.0375 mol

The given number of moles of K2CrO4 (0.04 mol) is more than the required number of moles (0.0375 mol). Therefore, AgNO3 is the limiting reagent.

Step 4:

According to the reaction, the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Hence, the number of moles of Ag2CrO4 formed is 0.0375 mol.

The molar mass of Ag2CrO4 is 331.74 g/mol.

The mass of Ag2CrO4 is calculated as:

Mass = 0.0375 mol x 331.74 g/mol

= 12.44 g

Learn more about precipitation here:

brainly.com/question/13859041

#SPJ4

6 0
2 years ago
A sample of urea contains 1.121 g of N, 0.161 g of H, 0.48 g of C, and 0.64 g of O. What is the empirical formula of urea?
dybincka [34]

Answer:

The empirical formula is N2 CH4 O

Explanation:

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3 years ago
1.34 milligrams is the same as _____ kg and _____g.
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Answer C is for kg and but it's .00134 for grams
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7 0
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Why don’t all of the particles in an atom contribute to the mass?
kotegsom [21]

Answer:

Explanation:

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Hope this helped!

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