M1 v1 = (m1 + m2)v2.
All of the exponents should be lowered to the bottom right of the letters.
Answer:
Explanation:
Due to first charge , electric field at origin will be oriented towards - ve of y axis.
magnitude
Ey = -8.99 x 10⁹ x 4.1 x 10⁻⁹ / 1.08² j
= - 31.6 j N/C
Due to second charge electric field at origin
= 8.99 x 10⁹ x 3.6 x 10⁻⁹ / 1.2²+ .6²
= 8.99 x 10⁹ x 3.6 x 10⁻⁹ / 1.8
= 18 N/C
It is making angle θ where
Tanθ = .6 / 1.2
= 26.55°
this field in vector form
= - 18 cos 26.55 i - 18 sin26.55 j
= - 16.10 i - 8.04 j
Total field
= - 16.10 i - 8.04 j + ( - 31.6 j )
= -16.1 i - 39.64 j .
Ex = - 16.1 i
Ey = - 39.64 j .
Answer:
15mm
Explanation:
We know that for circular holes first dark spot is given by
sin စ = 1.22 λ/D
Also we know that at the same time
tan စ = r/L
So
r = L tanစ = 6 x tan( arcsin(1.22x 500 x10^9/0.50 x 10^ 3))
= 0.0073 m = 7.3 mm
However since the size is twice that so 14.6 mm which is approx 15mm
Answer:
160N/m
Explanation:
According to Hooke's law which states that the extension of an elastic material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically,
F = ke where
F is the applied force
k is the spring constant
e is the extension
From the formula k = F/e
Since the body accelerates when the block is released, F = ma according to Newton's second law of motion.
The spring constant k = ma/e where
m is the mass of the block = 0.4kg
a is the acceleration = 8.0m/s²
e is the extension of the spring = 2.0cm = 0.02m
K = 0.4×8/0.02
K = 3.2/0.02
K = 160N/m
The spring constant of the spring is therefore 160N/m
Answer:
0.043 m
Explanation:
From the attachment, the shaded part is the ethyl alcohol. The crossed part on the other hand, is that of glycerin.
The height of the Ethyl Alcohol is h2 = 0.25 m, it's density is ρ2 = 790 kg/m³. The density of glycerin is ρ1 = 1260 kg/m³
If we assume pressure at the two points to be the same, then
P1 = P2
ρ1.g.V1 = ρ2.g.V2
ρ1.A.h1 = ρ2.A.h2
ρ1.h1 = ρ2.h2, making h1 subject of formula
h1 = ρ2.h2 / ρ1, so that
h1 = 790 * 0.25 / 1260
h1 = 197.5 / 1260
h1 = 0.157 m
Δh = 0.2 - 0.157
Δh = 0.043 m or 4.3 cm
