Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm
until the height of the alcohol column is 25 cm. The two liquids do not mix. What is the difference in height between the top surface of glycerin and the top surface of alcohol?
1 answer:
Answer:
0.043 m
Explanation:
From the attachment, the shaded part is the ethyl alcohol. The crossed part on the other hand, is that of glycerin.
The height of the Ethyl Alcohol is h2 = 0.25 m, it's density is ρ2 = 790 kg/m³. The density of glycerin is ρ1 = 1260 kg/m³
If we assume pressure at the two points to be the same, then
P1 = P2
ρ1.g.V1 = ρ2.g.V2
ρ1.A.h1 = ρ2.A.h2
ρ1.h1 = ρ2.h2, making h1 subject of formula
h1 = ρ2.h2 / ρ1, so that
h1 = 790 * 0.25 / 1260
h1 = 197.5 / 1260
h1 = 0.157 m
Δh = 0.2 - 0.157
Δh = 0.043 m or 4.3 cm
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Answer:
0.108 rad/s².
Explanation:
Given that
Initial angular velocity ,ωi = 0 rad/s
Final angular velocity ωf= 0.5 rev/s
We know that
1 rev/s = 6.28 rad/s
ωf= 3.14 rad/s
t= 28.9 s
We know that (if acceleration is constant)
ωf=ωi + α t
α=Angular acceleration
3.14 = 0 + α x 28.9
Therefore the acceleration will be 0.108 rad/s².
Therefore the answer will be 0.108 rad/s².