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motikmotik
3 years ago
9

Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm

until the height of the alcohol column is 25 cm. The two liquids do not mix. What is the difference in height between the top surface of glycerin and the top surface of alcohol?

Physics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

0.043 m

Explanation:

From the attachment, the shaded part is the ethyl alcohol. The crossed part on the other hand, is that of glycerin.

The height of the Ethyl Alcohol is h2 = 0.25 m, it's density is ρ2 = 790 kg/m³. The density of glycerin is ρ1 = 1260 kg/m³

If we assume pressure at the two points to be the same, then

P1 = P2

ρ1.g.V1 = ρ2.g.V2

ρ1.A.h1 = ρ2.A.h2

ρ1.h1 = ρ2.h2, making h1 subject of formula

h1 = ρ2.h2 / ρ1, so that

h1 = 790 * 0.25 / 1260

h1 = 197.5 / 1260

h1 = 0.157 m

Δh = 0.2 - 0.157

Δh = 0.043 m or 4.3 cm

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Keith_Richards [23]

Answer:

Density =0.74 g/cm^{3}

Explanation:

Step 1: Formula

 Density=\frac{Mass}{Volume}

Step 2: Data

m=278 g

v=375 cm^{3}

Step 3:Solve

d= \frac{278}{375} g/cm^{3}

d=0.74 g/cm^{3}

8 0
3 years ago
The kinetic friction force between a 60.0-kg object and a horizontal surface is 50.0 N. If the initial speed of the object is 25
Vikki [24]

Answer:

375 m.

Explanation:

From the question,

Work done by the frictional force = Kinetic energy of the object

F×d = 1/2m(v²-u²)..................... Equation 1

Where F = Force of friction, d = distance it slide before coming to rest, m = mass of the object, u = initial speed of the object, v = final speed of the object.

Make d the subject of the equation.

d = 1/2m(v²-u²)/F.................. Equation 2

Given: m = 60.0 kg, v = 0 m/s(coming to rest), u = 25 m/s, F = -50 N.

Note: If is negative because it tends to oppose the motion of the object.

Substitute into equation 2

d = 1/2(60)(0²-25²)/-50

d = 30(-625)/-50

d = -18750/-50

d = 375 m.

Hence the it will slide before coming to rest = 375 m

6 0
3 years ago
Your friend says that inertia is a force that keeps things in their place, either at rest or in motion. Do you and your discussi
Galina-37 [17]

Answer:

yes i agree

Explanation:

because law of inertia state that object remain at rest or in motion unless external force apply on it

8 0
3 years ago
A figure skater glides along a circular path of radius 6.70 m. If she coasts around one half of the circle, find the following.
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(a) Her distance from the starting location is 21.05 m.

(b) The length of the path she skated is 21.05 m.

<h3>Distance of the skater from the starting position</h3>

The distance around a complete circular path is calculated as 2πr.

The distance for a half circle is calculated as ¹/₂ x 2πr = πr

Distance from the starting location = π x 6.7 m = 21.05 m

The length of the path she skated is the same as her distance from the starting location = 21.05 m.

Learn more about distance round a circle here: brainly.com/question/3100527

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8 0
2 years ago
(a) An object that has a small mass and an object that has a large mass have the same momentum. Which object has the largest kin
Iteru [2.4K]

Answer:

A) The smaller object; B) The larger object

Explanation:

A) Lets say the small object is 2 kg and the large one is 6 kg. Lets say they also have 30 kg*m/s of momentum each. The small object would have 15 m/s velocity and the large would have 5 m/s.

Now for kinetic energy(.5*m*v²), the small object is .5*2*15², which is 225 J

The large object is .5*6*5², which is 75 J, so the smaller object has more Kinetic energy. Since velocity is squared, it is more important than how large mass is.

B) Same masses as part A. Lets say the kinetic energy is 45 J for both of them. For the small object, 45=.5*2*v²

.5*2 is 1, so 45/1 is 45. Take the square root and we get v= 6.71 m/s

For the large object, 45=.5*6*v²

.5*6 is 3, so 45/3 is 15. Take the square root and we get v=3.87 m/s

Now we plug the velocities into p=mv

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For the large object, p=6*3.87, which gives us p=23.22 kg*m/s

The larger object has the larger momentum.

Hope this helps

5 0
3 years ago
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