Fe2(SO4)3.3H2O = 56*2 + 3*(32+16*4)+3*(1*2+16) = 454 g/mol
Mol =m/M = 10.5/454 = 0.023 mol
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Since according to ideal gas law, PV=nRT and you have 1.2atm, plug in the value for volume but make sure to convert to L instead of mL and convert temperature to Kelvin
These are two questions and two answers.
Answers:
Explanation:
<u>1) Balanced chemical equation (given):</u>
- CO₂(g) + 4H₂(g) → CH₄(g) + 2H₂O(g)
<u>2) Part A: How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas? </u>
a)<u> Mole ratios:</u>
- 1 moles CO₂(g) : 1 mole CH₄(g)
b) <u>Proportion:</u>
- 1 moles CO₂ / 1 mol CH₄ = 59.6 moles CO₂ / x
⇒ x = 59.6 mol CH₄ ← answer
<u>3) Part B How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 42.1 moles of water vapor? </u>
a) <u>Mole ratios:</u>
- 4 mol H₂(g) : 2 mol H₂O(g)
b) <u>Proportion:</u>
- 4 mol H₂ / 2 mol H₂O = x / 42.1 mol H₂O
⇒ x = 42.1 × 4 / 2 moles CH₄ = 84.2 mol H₂ (g) ← answer
<h2>
Answer: 448254.609 mm³ OR 4.48 × 10⁵ mm³ </h2>
Explanation:
Volume = Mass ÷ Density
= 0.08 g ÷ 0.17847 g/L
= 0.448254609 L
since 1 L = 1,000,000 mm³
then 0.448254609 L = 448254.609 mm³