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Nookie1986 [14]

3 years ago

15

Many towns in flood-prone areas are surrounded by___ that are built to hold back rising water.

1 answer:

xxTIMURxx [149]3 years ago

8 0

Answer:

Flood barriers

Explanation:

Many towns in flood-prone areas are surrounded by flood barriers that are built to hold back rising water during seasonal highs.

Flood barriers are water resistant walls that are used to prevent breaking water during a high period of inundation from their channels.
They are usually vertical artificial structures which can be temporary or permanent.
They help to hold or contain the flood water during the high season.
These walls prevents flood plains and other nearby areas from getting flooded during the rainy season.

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Mass of 2×10^21 number of atoms of an element is 0.4g. What is the mass of 0.5 mole of the element?

alexandr402 [8]

Answer:

66.7 g

Explanation:

Number of atoms = 2×10²¹

Mass of 2×10²¹ atoms = 0.4 g

Mass of 0.5 moles of that element = ?

Solution:

1 mole contain 6.022×10²³ atoms

2×10²¹ atoms × 1 mol / 6.022×10²³ atoms

0.33×10⁻² mol

0.003 mol

0.003 mole have mass of 0.4 g

0.5 mol have mass 0.5/0.003×0.4 g = 66.7 g

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the value of kc for the following reaction is 0.630 at 409 K N2O4(g) --> 2NO2(g) if a reaction vessel at that temperature int

stealth61 [152]

<u>Answer:</u> The concentration of nitrogen dioxide at equilibrium is 0.063 M

<u>Explanation:</u>

We are given:

Initial concentration of nitrogen dioxide = 0.0250 M

Initial concentration of dinitrogen tetraoxide = 0.0250 M

For the given chemical equation:

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

<u>Initial:</u> 0.025 0.025

<u>At eqllm:</u> 0.025-x 0.025+2x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

We are given:

$K_c=0.630$

Putting values in above expression, we get:

$0.630=\frac{(0.025+2x)^2}{(0.025-x)}\\\\x=-0.2013,0.019$

Neglecting the negative value of 'x', because concentration cannot be negative

So, equilibrium concentration of nitrogen dioxide = (0.025 + 2x) = [0.025 + 2(0.019)] = 0.063 M

Hence, the concentration of nitrogen dioxide at equilibrium is 0.063 M

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Answer:

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sergejj [24]

Answer:

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Explanation:

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Aloiza [94]

5.00 x 1011/s = 5.05500kilohertz

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