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3 years ago

Total number of faculty is 136. There are 6 professors to every 11 lecturers. How many professors are there

Mathematics

1 answer:

laila [671]3 years ago

3 0

Answer:

The Total number of Professors = 48

Step-by-step explanation:

Given as,

The total number of Faculty = 136

And the Ratio of Professors to Lecturers = 6 Ratio 11

Now According to question

Professors : Lecturers = 6 : 11

So, Let the Number of Professors = 6x

And The Number of Lecturers = 11x

∴ 6x + 11x = 136

Or, 17x = 136

Or, x = $\frac{136}{17}$ = 8

Hence, the number of Professors = 6 × 8 = 48 Answer

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3 years ago

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$= 2 \times ( \frac{1}{2} \pi {r}^{2} )$

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2 years ago

Read 2 more answers

1 2/5m-3/5(2/3m+1) How do you solve this problem

igor_vitrenko [27]

Step-by-step explanation:

I am not sure what you mean by "solve".

I assume you mean simplify the expression.

and then it is very tricky to find the true original expression the way you typed it.

I think you meant

1 2/(5m) - 3/(5(2/(3m + 1)))

1 = 5m/5m

1 2/(5m) = (5m+2)/5m

3/(5(2/(3m + 1))) = 3/(10/(3m + 1)) = 3/1 / (10/(3m + 1))

when dividing by a fraction, it is the same as multiplying with the upside-down fraction

so, this is the same as

3/1 × (3m + 1)/10 = (3(3m + 1)) / (10×1) = (9m + 3)/10

this would give us in total

(5m + 2)/5m - (9m + 3)/10

to do the subtraction we need to bring both fractions to the save denominator (lower part).

it seems to me the easiest one would be 10m.

so,

2×(5m + 2)/10m - m×(9m + 3)/10m =

= (10m + 4)/10m - (9m² + 3m)/10m =

= (10m + 4 - 9m² - 3m)/10m = (-9m² + 7m + 4)/10m

if we want to transform this back to a sum of fractions :

4/10m - (9m² - 7m)/10m = 2/5m - (9m - 7)/10

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2 years ago