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kirill115 [55]
3 years ago
7

What is the wavelength of an electromagnetic wave that travels at 3 10 m/s and has a frequency of 60 mhz? (1 mhz = 1,000,000 hz)

?
Physics
2 answers:
Dahasolnce [82]3 years ago
8 0
V = 310 m/s
f = 60 MHz = 60 × 10^6 Hz
v = xf
x = v/f
x = 310/(60 × 10^6) m
x = 5.166667 × 10^(−6) m
kolezko [41]3 years ago
8 0

Answer:

\lambda = 5 m

Explanation:

As we know the electromagnetic waves can travel through the vacuum with speed

c = 3 \times 10^8 m/s

now we also know that the frequency of the electromagnetic waves is given as

f = 60 MHz

so the wavelength of the electromagnetic waves is given as

\lambda = \frac{c}{f}

so it is given as

\lambda = \frac{3 \times 10^8}{60 \times 10^6 Hz}

\lambda = 5 m

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Explanation:

A charge alters the space around it. This alteration of space is called the electric field. It is also defined as the electric force acting on a charged particle per unit test charge. It is given by :

E=\dfrac{F}{q}

Where

F is the electric force, F=\dfrac{kq_1q_2}{r^2}

The direction of electric field is in the direction of electric force. For a positive charge, the direction of electric field lines are outwards and for a negative charge, the direction of field lines are inwards.

Hence, the correct option is (c) "electric field".

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3 years ago
Graph the following data tables on different graphs.
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Answer:

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2 years ago
A cat has a mass of 4.6 kg. What is its weight on Earth's surface?
andreyandreev [35.5K]
<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

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weight = 45.126

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4 0
3 years ago
Read 2 more answers
a car accelerates from rest at 3.6m/s^2. how much time does it need to attain a speed of 7 m/s? awnser in units of s.
Ivahew [28]
Initial velocity: 0
final velocity: 7 m/s
a = 3.6
t = ?
x = ?

(7-0)/3.6 = t
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6 0
3 years ago
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41. Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 h
romanna [79]

Answer:

138.3 days

Explanation:

Given that a Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 has been discovered and has a radius of 7.8 X 10 meters.

The period of time for Clayton J-21 to orbit Dayli can be calculated by using Kepler law.

T^2 is proportional to r^3

That is,

T^2/r^3 = constant

98^2 / 62^3 = T^2 / 78^3

Make T^2 the subject of formula.

T^2 = 98^2 / 62^3 × 78^3

T^2 = 19123.2

T = sqrt ( 19123.2 )

T = 138.2867 days

Therefore, the period of time for Clayton J-21 to orbit Dayli is 138.3 days approximately.

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