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3 years ago

What is the initial velocity of the object represented by the graph?

Physics

2 answers:

jenyasd209 [6]3 years ago

6 0

Answer:

5m/s

Explanation:

Arturiano [62]3 years ago

5 0

Initial velocity of the object: 5 m/s

Explanation:

The figure in the problem is missing: find it in attachment.

The graph in the figure represents the velocity of an object (v) versus the time passed (t).

Here we are asked to find the initial velocity of the object.

This means that we have to find the velocity of the object when the time is zero, so when

t = 0

By looking at the corresponding value on the y-axis (velocity), we see that when t = 0, then

v = 5 m/s

Therefore, the initial velocity of the object is 5 m/s.

Learn more about velocity:

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The pressure at the bottom of a cylindrical container with a cross-sectional area of 45.5 cm2 and holding a fluid of density 420

iris [78.8K]

Answer:

3.33 m

Explanation:

Pressure is the distributed force applied to the surface of an object per unit area. The force is applied perpendicular to the surface of the object. The SI unit of pressure is N/m² or Pa.

Hydrostatic pressure is the pressure that a fluid exerts at a point due to the force of gravity.

The relationship between pressure on the bottom of the container, atmospheric pressure and the pressure due to the depth of the fluid is given by:

$P_{bottom}-P_{atm}=P_{depth}\\\\where\ P_{bottom}=pressure\ at\ the \ fluid\ bottom,\ P_{atm}=atmospheric\ pressure\\P_{depth}=pressure\ due\ to\ fluid\ depth=\rho gh. \ Hence:\\\\P_{bottom}-P_{atm}=\rho gh\\\\Given \ that\ P_{bottom}=115\ kPa=115*10^3\ Pa, let\ us\ assume\ P_{atm}=101\ kPa=101*10^3\ Pa,\rho=420\ kg/m^3,g=acceleration\ due\ to \ gravity=10\ m/s^2.\\\\Therefore:\\\\115*10^3-101*10^3=420*10*h\\\\14*10^3=4200h\\\\h=3.33\ m\\\\$

6 0

4 years ago

The energy lost to friction is destroyed.TrueFalse

leva [86]

False!!!!!!!!!!!!!!!!!!

5 0

3 years ago

A football quarterback runs 15.0 m straight down the playing field in 2.30 s. He is then hit and pushed 3.00 m straight backward

Monica [59]

Answer:

6.52 m/s

1.72 m/s

5.38 m/s

Explanation:

this question requires us to find the average velocity.

1. velocity in straight down direction:

velocity = distance/time

= 15.0/2.30

= 6.52 m/s

2. velocity in straight backward direction:

velocity = distance/time

= 3.00 /1.74

= 1.72m/s

3. velocity in straight forward direction

velocity = distance/time

= 28.0/5.20

= 5.38 m/s

these are the his velocities for each if the intervals.

thank you!

7 0

3 years ago

Goodmorning I can’t seem to remember this can someone help me

Bumek [7]

Explanation:

3 cause the triangle method of addition are connected to tips of one vector

6 0

3 years ago

The fragments collided with Jupiter's atmosphere at a speed of about 60,000 m/s

Mazyrski [523]

Answer: E = 5.004*10^(20) joules

Explanation:

We do not have a lot of information about the impact, so we can assume that the energy released on the impact was the kinetic energy of the large fragment.

Remember that the kinetic energy of an object of mass M that moves at a velocity V is:

K = (M/2)*V^2

in this case, we know that the speed (that is equivalent to the velocity) is:

V = 60,000 m/s

And the mass is:

M = 1.39*10^(11) kg

Then the kinetic energy of the large fragment was:

K = (1.39*10^(11) kg/2)*( 60,000 m/s)^2 = 5.004*10^(20) joules.

Then we could conclude that the energy released on the impact was:

E = 5.004*10^(20) joules

3 0

3 years ago