3 years ago

Do noble gases lose or gain electrons to get a full valence shell?

Physics

1 answer:

alexdok [17]3 years ago

8 0

They don't lose OR gain electrons as they've already achieved the octet rule and have 8 valence electronsn

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The cylinder in the picture is rotating at 500 RPMs. The friction coefficients between the cylinder and block B are static=0.5 a

Tju [1.3M]

Coefficient of static friction = 0.5
Coefficient of Kinetic friction = 0.3
Angular velocity = 500 RPMs

<h3>The Radius of the System</h3>

Let R be the radius of cylinder

$m_a + m_b = 4 + 3 = 7kg$

The angular velocity is 500 RPMs

$\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R$

The normal force

$f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm$

Since the radius is very little for two block to execute circular motion so system will slide down.

Learn more on coefficient of static friction here;

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2 years ago

Which of these statements is true?

balu736 [363]

Imma go with A.

Hope this helps:)

8 0

3 years ago

Read 2 more answers

Which of these objects would need the largest force to create an acceleration of 1 m/s2?

babymother [125]

I think the answer is D the 30 kg sofa

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4 years ago

Suppose a straight wire with a length of 2.0 m runs perpendicular to a magnetic field with a magnitude of 38 T. What current wou

iragen [17]

Answer:

9.67 A

Explanation:

The weight of a student with a mass of m = 75 kg is:

$W=mg=(75 kg)(9.8 m/s^2)=735 N$

where g=9.8 m/s^2 is the acceleration due to gravity.

We want the magnetic force on the wire to be equal to this weight. The magnetic force on the wire is

$F=ILB sin \theta$

where

I is the current in the wire

L = 2.0 m is the length of the wire

B = 38 T is the magnetic field

$\theta=90^{\circ}$ is the angle between the direction of B and L

Since we want W=F, we can write

$ILB sin \theta=W$

And we can solve it to find the current I:

$I=\frac{W}{BLsin\theta}=\frac{735 N}{(38 T)(2.0 m)(sin 90^{\circ})}=9.67 A$

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3 years ago

What happens when a hockey puck slides on a perfectly frictionless surface?

oksian1 [2.3K]

It will slide for ever in the same direction, unless it hits an object! Please give me the brainlest answer1

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3 years ago