A light wave that hits the surface of a pool gets refracted and gives us an apparent image of the surface of the pool, following the concepts of refraction.
<u>Explanation:</u>
Let’s recall the concept of refraction when a light wave passes from medium of rarer to denser. There is a change in the speed of light while travelling from medium of rarer to denser.
There can be a change in the direction as well. This property is known as “Refraction” and the best example to see refraction is watching the surface of a clean pond, lake or pool.
When the light travels from a rarer medium (air) to a denser medium (water), it changes its angle of direction and gets refracted and hit to our eye lenses. With this, we see the surface of the pool at a changed angle and it seems to be a bit shallow than its original depth.
The equation we need to use is Ohm's Law
Voltage = Current * Resistance
Voltage = 6A * 3<span>Ω = 18 Volts</span>
Explanation:
I think its a option pascal's principal
Alpha particles are released by proton rich unstable nuclei. It has no electrons to balance the protons making it positively charged particles moving at very high speeds. Gamma articles are electromagnetic waves of short wavelength and high frequency. It has a speed same as the speed of light. Beta particles are released by neutron rich unstable nuclei. It has a speed of less than the gamma particles.
Answer:
The two possible frequencies of the other player's note are 437.3 Hz and 442.7 Hz
Explanation:
Given Data
f₁=440 Hz
fₐ=2.7 beats per seconds
The beat frequency is equal to the difference in the frequencies of the two original waves:
So
f
=|(f₁±fₐ)|
First to Solve for (-) Sign we get
f=|(440-2.7)|
f=437.3 Hz
Now for Solve for (+) Sign we get
f=|(440+2.7)|
f=442.7 Hz
The two possible frequencies of the other player's note are 437.3 Hz and 442.7 Hz
