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leva [86]
3 years ago
12

Three equivalent forms of a quadratic function are given. Select the form which reveals the zeros of f(x) without needing to alt

er the equation. Then, select all values for x from the given list when f(x) = 0.
Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

Read explanation and apply it

Step-by-step explanation:

The vertex form of a quadratic equation is  f(x)=a(x-h)^2+k

The general form of a quadratic equation is f(x)=ax^2+bx+c

The factored form of a quadratic equation is f(x)=a(x-p)(x-q)

The one which reveals the zeros of f(x) without needing to alter the equation is the factored form  f(x)=a(x-p)(x-q).

When f(x)=0, we have  a(x-p)(x-q)=0

The values of x are x=p and x=q.

I hope this guides you to choose the correct answer.

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sineoko [7]

Answer:

a) P(x > 120) = 0.74537

b) P(100 < x < 110) = 0.46777

c) Value of a = 110.7

Step-by-step explanation:

Let x = amount of miraculin produced (measured in micro grams per gram of fresh weight)

We are given <em>Mean, </em>\mu<em> = 105.3  and  Standard Deviation, </em>\sigma<em> = 8.0</em>

Also, since x is normally distributed so;

                    Z = \frac{x - \mu}{\sigma} follows N(0,1)

a) P(x > 100) = P( \frac{x - \mu}{\sigma} > \frac{100 - 105.3}{8.0} ) = P(Z > -0.6625) = P(Z < 0.66) = 0.74537

b) P(100 < x < 110) = P(x < 110) - P(x <= 100)

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Hence, <em>P(100 < x < 110) = 0.72240 - 0.25463 = 0.46777</em>

c) Given expression is P(x < a ) = 0.25

                       ⇒ P( \frac{x - \mu}{\sigma} < \frac{a - 105.3}{8.0} ) = 0.25

                       ⇒ P(Z < \frac{a - 105.3}{8.0} ) = 0.25

By seeing the Z % table we find that the value of z which have an are of 25% is 0.6745 i.e.

                     \frac{a - 105.3}{8.0} = 0.6745

So, value of a = 0.6745*8 + 105.3 = 110.7 .        

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