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alex41 [277]
3 years ago
14

Now suppose that the file is broken into 5 packets, each of 10 Mbits. Ignore headers that may be added to these packets. Also ig

nore router processing delays. Assuming store and forward packet switching at the router, what is the total delay?
Computers and Technology
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

6.025seconds

Explanation:

For each link we have,

Dtran = 10mbits/10mbps =1 second

Dprop = 5000km/2×10^8m/sec =0.025sec.

Total delay =( 5 + 2-1) + Dtran+ 2 Dprop= 6.025seconds

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You have to display or connect to network shares on remote computers. Which command-line utility will you use to accomplish the
Xelga [282]

Answer:

net use X: \\SERVER\Share

Explanation:

1. Connect securely to the remote computer or ensure you have access to it on the network

2. then follow the step below:

Where X: is the drive letter you wish to map the share to, and \\SERVER\Share is the UNC path to the share. This should make the share visible in My Computer and the command line as well like all other shares mapped through the GUI.

In order to later disconnect the share, you would use

net use X: /delete

8 0
3 years ago
Write the interface (.h file) of a class Counter containing: A data member counter of type int. A data member named counterID of
OlgaM077 [116]

Explanation:

See the attached image for The interface (.h file) of a class Counter

8 0
3 years ago
Write a MIPS assembly language program that
8_murik_8 [283]

Answer:

123456789098765432

Explanation:

asdfghjklokjhgfdsasertyujn nbgfdfvbnjujhgvfcdec vgfredfghjmk

5 0
3 years ago
Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have alre
Fudgin [204]

Answer:

The c++ program to implement the while loop is given below.

#include <iostream>

using namespace std;

int main() {

  // declaration of integer variables

   int k, n, total;

   // initialization of integer variables

   k=1, n=4, total=0;

//  loop executed till value of k becomes equal to value of n

   while( k <= n ){

       // cube of every integer is added to the variable total

       total = total + ( k * k * k );

       // value of k is incremented to go to the next number

k = k + 1 ;

   }  

   return 0;

}  

Explanation:

The program begins with the declaration of integer variables.  

int k, n, total;

This is followed by initialization of these variables.

k=1, n=4, total=0;

The while loop runs over the variable k which is initialized to 1. The loop runs till value of k reaches the value of integer n.

First, cube of k is computed and added to the variable total.

After first execution of the loop, total is initialized to the cube of 1.

Next, value of variable k is incremented by 1 so that k is initialized to next integer.

After first execution of the loop, k is incremented from 1 to 2.

while( k <= n )

{

total = total + ( k * k * k );

k = k + 1 ;

   }

When the value of k reaches the value of integer n, the cube of n is calculated and added to the variable, total.

When k is incremented, it becomes more than n and hence, loop gets terminated.

As the return type of main is int, the program terminates with the statement shown below.

return 0;

No output is displayed as it is not mentioned in the question.

No user input is taken as it is mentioned that integer variables are already initialized.

4 0
2 years ago
what is the largest possible number of internal nodes in a redblack tree with black height k? what is the smallest possiblenumbe
Elina [12.6K]

Answer:

A Red Black Tree is a type of self-balancing(BST) in this tree ,each node is red or black colored. The red black tree meets all the properties of the binary search tree, but some additional properties have been added to a Red Black Tree.

A Red-Black tree's height is O(Logn) where (n is the tree's amount of nodes).

In a red-black tree with black height k

The maximum number of internal nodes is 2^{2k} -1.

The smallest possible number is 2^{k} -1.

7 0
2 years ago
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