Answer: 280dm3
Explanation:Please see attachment for explanation
Answer:
Extreme heat will cause the substance molecules to move faster and cause a phase change this phase change would occur if left in an extremely hot area causing the molecules to spread apart.
Explanation:
Answer:
Oxidation states are used in chemistry solutions. It is a bond in which electron transfers easily from one nucleus to another nucleus.
Explanation:
- Oxidation-reduction reactions have some rules.
- The oxidation state is 0 at an uncombined bond.
- The bond of oxidation reduction is +1 in alkeli metal.
- The bond in two metal is +2
- The oxidation reduction state at helogens is -1. It does not happened always.
- The oxygen bond in oxidation and reduction is -2.
- The sum of the oxidation state is equal to the compound charges.
- In this process the changes occur for any elements. Redox could be occur. Its oxidized and reduction reaction can be seen in this process.
The balanced equation for the reaction is as follows;
2H₂S + SO₂ —> 2H₂O + 3S
Stoichiometry of H₂S to SO₂ is 2:1
Limiting reactant is fully used up in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of H₂S moles - 8.0 g / 34 g/mol = 0.24 mol of H₂S
Number of SO₂ moles = 12.0 g / 64 g/mol = 0.188 mol of SO₂
According to molar ratio of 2:1
If we assume H₂S to be the limiting reactant
2 mol of H₂S reacts with 1 mol of SO₂
Therefore 0.24 mol of H₂S requires - 1/2 x 0.24 = 0.12 mol of SO₂
But 0.188 mol of SO₂ is present therefore SO₂ is in excess and H₂S is the limiting reactant.
H₂S is the limiting reactant
Amount of S produced depends on amount of H₂S present
Stoichiometry of H₂S to S is 2:3
2 mol of H₂S forms 3 mol of S
Therefore 0.24 mol of H₂S forms - 3/2 x 0.24 mol = 0.36 mol of S
Mass of S produced = 0.36 mol x 32 g/mol = 11.5 g of S is produced
Answer:
1.35
Explanation Use the mole formla and multiply and them apply the sig fig rules and you will get the moles of water hope this helps god bless
