Largest
K
Ca
Ga
Ge
As
Br
Kr
Smallest
Answer:
32.4%
Explanation:
Given parameters:
Mass of hydrated sample = 25g
Mass of anhydrous salt = 16.9g
Unknown:
Percentage of water in the hydrate = ?
Solution:
Obviously, there is a mass difference between the original hydrated sample and anhydrous salt which should indicate clearly that the mass loss is due to the evaporated water from the salt.
Mass of salt of water = mass of hydrated salt - mass of anhydrous salt
= 25g - 16.9g
= 8.1g
Percentage of water =
=
= 32.4%
<h2>Hello!</h2>
The answer is: H2O
<h2>
Why?</h2>
The critical temperature (also known as the critical point) is the temperature above a vapor or gas can't be liquefied no matter how many pressure can be applied. Every substance has a critical temperature which varies according to the substance/compound nature.
For example, the water has a critical temperature of 373.94 °C, it means that above that temperature the vapor and liquid phases can't be distinct and there is no possible way that the vapor became liquid again no matter how many pressure is applied.
The critical temperature of the given elements/compounds are:
H2 : -240 °C
N2: -147 °C
NH3: 132.4 °C
H2O: 373.94 °C
Have a nice day!
Answer: The volume of the gas when the temperature of the gas is raised to is 363 ml
Explanation:
To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Thus the volume of the gas when the temperature of the gas is raised to if the pressure remains constant is 363 ml
The answer would be heptan-3-one and heptan-4-one.
The acid-catalyzed hydration of a balanced alkyne gives a
ketone.
R-C≡C-R + H₂O → R-CH₂-CO-R
If the alkyne is uneven, you get a combination of two
ketones, since the O can increase to either of the alkyne C atoms.
R-C≡C-R' + H₂O → R-CH₂-CO-R' + R-CO-CH₂-R'
So, for CH₃CH₂CH₂-C≡C-CH₂CH₃, the products are
CH₃CH₂CH₂-CH₂-CO-CH₂CH₃ and CH₃CH₂CH₂-CO-CH₂-CH₂CH₃
Their terms are heptan-3-one and heptan-4-one,