Answer:
height = 7 cm
Step-by-step explanation:
The area (A) of a trapezium is calculated using the formula
A =
h(a + b)
where h is the height and a, b the parallel bases
here a = 6, b = 12 and A = 63, hence
× h × (6 + 12) = 63
h × 18 = 63
9h = 63 ( divide both sides by 9 )
h = 7
We know that
4 3/4---------> (4*4+3)/4----------> 19/4
1 1/10-----------> (10*1+1)/10----> 11/10
[pounds left]=[(19/4)-(11/10)-(2)]----> (10*19-4*11-40*2)/40
=(190-44-80)/40-------> 66/40---------> 1.65 pounds
1.65-----> 1 65/100--------> 1 13/20 pounds
the answer is 1.65 pounds (1 13/20 pounds)
Let the width be x, then the length is 2x
2(x + 4 + 2x + 4) = 46
(3x + 8) = 46/2 = 23
3x = 23 - 8 = 15
x = 15/3 = 5 ft
Therefore, width is 5 feet and length is 2(5) = 10 feet
Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) = 
= 
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4
This is an isosceles triangle. The angles at the base are congruent (they have the same measures).
Look at the picture.
We know: The sum of the measures of angles in a triangle is equal 180°.
Therefore we have the equation:
<em>combine like terms</em>

<em>subtract 5 from both sides</em>
<em>divide both sides by 7</em>


<h3>Answer: D. m∠C = 40</h3>