You run 100 meters in 15 seconds. What is your speed in m/s? and show your work
1 answer:
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Answer:
Check the explanation
Explanation:
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
The image is virtual
The image is upright
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
Kindly check the diagram in the attached image below.
Explanation is in a file
bit.ly/3a8Nt8n
Explanation:
The particle will be at rest when its velocity is equal to zero. Recall that the velocity is simply the derivative of the position
with respect to time:
Since
then
Solving for t, we find that the particle will be at rest at
Answer:
False.
Explanation:
Yes the magnitude of a vector is always positive , but a vector consists of
- magnitude
- direction
when two vectors are added their direction may be opposite to each other For example-
,
then their resultant
This resultant vector's x and y component equal to y and x component of vector b so its magnitude will be equal to magnitude of vector b.
Therefore, the resultant magnitude not necessary equal to the magnitude of either vector.