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saw5 [17]
4 years ago
15

Given LM = ON and LO= MN. Prove LMNO is a parallelogram. What is the 6th 7th and 8th step

Mathematics
2 answers:
netineya [11]4 years ago
4 0

Answer:

6. LNO and NLM are alt. Interior angles.

7. OLN and MNL are alt. Interior angles

Both are def of alt interior angles

8. LNO = NLM. CPCT

AveGali [126]4 years ago
4 0

Answer:

Bruh moment

Step-by-step explanation:

awdawdawdawd

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On a citrus farm, the average annual yield of oranges is 124 pounds per tree when the number of trees is 22 per acre. For each a
ELEN [110]

Answer:

Number of orange trees = 3528

Step-by-step explanation:

Given: Average annual orange yield = 124 pounds (lbs) per tree

Number of trees = 22 per acre

Each tree produces 124 pounds, so 22 trees will produce

124*22 = 2728 lbs per acre

For every additional tree over 22, 2 pounds per tree is lost.

So, if you add x trees, you lose 2x pounds.

Thus, we have the function:

f(x) = (124 - 2x)*(22 + x) for the added tree(s)

f(x) = 2728 + 80x - 2x^{2}

For quadratic equations like this, the maximum(or minimum) is obtained by substituting x= -b/2a into the given equation. a and b are obtained from the general form of a quadratic equation:

y =ax^{2} + bx + c

Comparing this with f(x), we have that

a = -2 (coefficient of x2)

b = 80 (coefficient of x)

Using these values in x = -b/2a, we get

x = -\frac{80}{2*(-2)} = 20

So, use x = 20 in the maximum function we got earlier

f(x) = 2728 + 80(20) -2(20^{2}) = 2728 + 1600 - 800\\ \\f(x) = 3528

Therefore, the number of oranges that should be planted in order to maximize the number of pounds of oranges per acre = 3528

3 0
3 years ago
I need help asap.
DaniilM [7]
1+10 < or equal to 40
5 0
3 years ago
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10.) Sally cooks 6 pies and each pie is cut into 8 pieces. If she sells 36 pieces, what percentage did she sell
sasho [114]
75%, look at picture for work

7 0
3 years ago
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Answer this please thanks
taurus [48]

Answer:

No

Step-by-step explanation:

The first 3 boxes are proportional since they have a ratio of 1:3, but 6:21 is not proportional to the others.

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Write an equation of a piecewise defined function with the given conditions: domain is (-3, 2) u (2, ∞) range is (-1, ∞) functio
Korvikt [17]
\left \{ {{f(x)=x+2, -3\ \textless \ x\ \textless \ 2} \atop {f(x)=x-2, 2\ \textless \ x\ \textless \ infinity}} \right.

f(x) has to be close to -1 when x is close to -3, and so f(x) is increasing when x increases, and there are no numbers from -1 to ∞ that there is no f(x) value. In the first piece of the function <span>f(x) ranges from -1 to 4 and the second piece from 0 to ∞ so. The ranges had to overlap since it's not defined at x = 2.</span>
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