Answer:
153.86.
Step-by-step explanation:
Formula for area of a circle: A= Pi R (R is radius) squared. First fill in the numbers: 3.14x7^2 Then Solve for the squared: 7^2=49, then finally multiply 49x3.14 which gets you to 153.86.
19,7,and 61 im not sure about the last one
Answer:
Peter Jonathan Winston (March 18, 1958 – disappeared January 26, 1978) was an American chess player from New York City
Step-by-step explanation:
In late 1977, Winston attended a FIDE-rated tournament at Hunter College High School in New York City. Despite being one of the highest-rated players in the tournament, Winston lost all nine of his games. A few months later, on January 26, 1978, following further surprising game losses, Peter Winston vanished and was never heard from again. According to some sources, Winston's disappearance occurred when he left his home without money, identification, or luggage during a severe winter storm. Many chess players who were close to or acquainted with Winston claim that the champion chess player's mental health had deteriorated, along with his game performance, in the last few years of his life, and that the decline in his mental health may have led to his disappearance.
Answer:
90
Step-by-step explanation:
![\frac{27}{30} \times 100](https://tex.z-dn.net/?f=%20%5Cfrac%7B27%7D%7B30%7D%20%20%5Ctimes%20100)
so after we cut the nessecary we get 90%
Hope this helps you
Mark as the brainlist
thank you
![\bf \cfrac{4a}{3}-\cfrac{b}{4}=6 \qquad \qquad \cfrac{5a}{6}+b=13 \\\\\\ \textit{let us remove the denominators off those folks}\\ \textit{by multiplying the first one by 12, both sides}\\ \textit{and the second one by 6, both sides, thus} \\\\\\ 12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72 \\\\\\ 6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B4a%7D%7B3%7D-%5Ccfrac%7Bb%7D%7B4%7D%3D6%0A%5Cqquad%20%5Cqquad%20%0A%5Ccfrac%7B5a%7D%7B6%7D%2Bb%3D13%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Blet%20us%20remove%20the%20denominators%20off%20those%20folks%7D%5C%5C%0A%5Ctextit%7Bby%20multiplying%20the%20first%20one%20by%2012%2C%20both%20sides%7D%5C%5C%0A%5Ctextit%7Band%20the%20second%20one%20by%206%2C%20both%20sides%2C%20thus%7D%0A%5C%5C%5C%5C%5C%5C%0A12%5Cleft%28%20%5Ccfrac%7B4a%7D%7B3%7D-%5Ccfrac%7Bb%7D%7B4%7D%20%5Cright%29%3D12%286%29%5Cimplies%2016a-4b%3D72%0A%5C%5C%5C%5C%5C%5C%0A6%5Cleft%28%20%5Ccfrac%7B5a%7D%7B6%7D%2Bb%20%5Cright%29%3D6%2813%29%5Cimplies%205a%2B6b%3D78)
![\bf \textit{now, let's do the elimination} \\\\ \begin{array}{llll} 16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\ 5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\ &&--------\\ &&58a+0\quad=372 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%20%5Ctextit%7Bnow%2C%20let%27s%20do%20the%20elimination%7D%0A%5C%5C%5C%5C%0A%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A16a-4b%3D72%26%5Cboxed%7B%5Ctimes%203%7D%5Cimplies%20%2648a-%5Cunderline%7B12b%7D%3D216%5C%5C%5C%5C%0A5a%2B6b%3D78%26%5Cboxed%7B%5Ctimes%202%7D%5Cimplies%20%2610a%2B%5Cunderline%7B12b%7D%3D156%5C%5C%0A%26%26--------%5C%5C%0A%26%2658a%2B0%5Cquad%3D372%0A%5Cend%7Barray%7D)
solve for "a", once you get "a", plug it back into either equation to get "b"