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Nadusha1986 [10]

3 years ago

10

Which set of values is a function?

2 answers:

mojhsa [17]3 years ago

8 0

Answer:

1.

Step-by-step explanation:

For a function, you want each x-value to have one unique output, 1 passes that because we don't see any repeating x-values. 2 isn't a function because the point (9,5) and (9,-5) don't .work. If you plotted those points, that wouldn't pass the vertical line test. 3. has the same problem (3,4) and (3,8) and 4 with (5,9) and (5,-7).

I hope that helps?

:)

Veronika [31]3 years ago

3 0

The answer is Set 1

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The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

13.27 = t - 24.45

Alika [10]

Answer:

=

3

7

.

7

2

Step-by-step explanation:

Add

2

4

.

4

5

24.45

24.45

to both sides of the equation

1

3

.

2

7

=

−

2

4

.

4

5

1

3

.

2

7

+

2

4

.

4

5

=

−

2

4

.

4

5

+

2

4

.

4

5

4 0

2 years ago

G(x) = 5x + 3<br> Find G(2b)

GuDViN [60]

Answer:

G(2b) = 10b + 3

Step-by-step explanation:

To find G(2b), simply plug in 2b wherever there is an x in G(x).

G(x) = 5x + 3

G(2b) = 5(2b) + 3

G(2b) = 10b + 3

3 0

3 years ago

Read 2 more answers

Please help fast

lions [1.4K]

C. A chord because a chord is a line segment with 2 end points

5 0

3 years ago

Can anyone help me to solve these 2 questions please <br>I need very clear steps !!!!

DochEvi [55]

Hope this helps you

4 0

3 years ago