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kipiarov [429]
3 years ago
12

In analyzing the income statement of Bob Company, you see that cost of goods sold decreased from 2016 to 2017 by 8.2%. The cost

of goods sold was $19,000 in 2016. The cost of goods sold to the nearest cent in 2017 was A. $19,769.17. B. $17,442.00. C. $18,652.00. D. $20,679.71.
Mathematics
2 answers:
blsea [12.9K]3 years ago
7 0

Answer:

B

Step-by-step explanation:

the cost of goods sold in 2017 is

19,000−(19,000×0.082)=17,442

JulsSmile [24]3 years ago
7 0

<u>Answer: </u>

The correct answer option is B. $17,442.00.

<u>Step-by-step explanation: </u>

We know that for Bob Company, the total cost of goods sold in 2016 was $19,000.

In 2017, the total cost of goods sold dropped by 8.2% in comparison to the cost of goods sold in 2016.

Finding the dropped cost:

8.2% × 19000 = \frac{8.2}{100} × 19000

= $1558

So the cost of goods sold in 2017 = 19000 - 1554 = $17442


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A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
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Step-by-step explanation:

Universal set

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The number that like Twix.

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The number that like Reeses

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n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

5 0
2 years ago
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