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Whitepunk [10]
2 years ago
6

The element carbon exists in several different forms. Pure carbon can be found in the form of diamonds, coal, and the graphite i

n your pencil. Which statement concerning carbon is FALSE?
A) All carbon atoms have 6 protons.
B) All carbon atoms have 6 neutrons.
C) All carbon atoms have an atomic mass equal to the number of protons and neutrons.
D) All carbon atoms have an atomic number of 6.
Chemistry
1 answer:
UNO [17]2 years ago
7 0

Answer:

B) All carbon atoms have 6 neutrons.

Explanation:

The false statement from the given choices is that all carbon atoms have 6 neutrons.

There is a phenomenon called isotopy in chemistry.

Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their various nuclei.

  • These atoms of elements are called isotopes.
  • Carbon atoms generally have proton number of 6 which is the same as the atomic number.
  • As with all atoms, the mass number or atomic mass equals the number of protons and neutrons.

For the isotopes of carbon, their number of neutrons differs.

 For example:

            <em>¹²₆C                           ¹³₆C                        ¹⁴₆C</em>

The number of neutrons differs in the above isotopes.

 Number of neutrons = mass number - atomic number;

    ¹²₆C  , number of neutrons  = 12 - 6  = 6

      ¹³₆C, number of neutrons  = 13 - 6  = 7

       ¹⁴₆C, number of neutrons = 14 - 6  = 8

Therefore, based on the concept of isotopy, all carbon atoms do not have 6 neutrons.

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g Determine the empirical formula for a compound that contains C, H and O. It contains 40.92% C, 4.58% H, and 54.50% O by mass.
Lady bird [3.3K]

Answer:

The empirical formula for the compound is C3H4O3

Explanation:

The following data were obtained from the question:

Carbon (C) = 40.92%

Hydrogen (H) = 4.58%

Oxygen (O) = 54.50%

The empirical formula for the compound can be obtained as follow:

C = 40.92%

H = 4.58%

O = 54.50%

Divide by their molar mass

C = 40.92/12 = 3.41

H = 4.58/1 = 4.58

O = 54.50/16 = 3.41

Divide by the smallest i.e 3.41

C = 3.41/3.41 = 1

H = 4.58/3.41 = 1.3

O = 3.41/3.41 = 1

Multiply through by 3 to express in whole number

C = 1 x 3 = 3

H = 1.3 x 3 = 4

O = 1 x 3 = 3

The empirical formula for the compound is C3H4O3

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