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Nikolay [14]
3 years ago
5

rank these species by their ability to act as an oxidizing agent from best oxidizing agent to best reducing agent. Ag+ cr3+ sn2+

Na+
Chemistry
2 answers:
jolli1 [7]3 years ago
7 0

Answer: Order of the species in their decreasing oxidizing agent ability is Ag^+>Sn^{2+}>Cr^{3+}>Na^+

Explanation: Oxidizing agent is defined as the agent which helps the other element to get oxidized and it itself gets reduced. These agents should have a positive value of reduction potentials. More is the positive value, best is the oxidizing agent.

Reducing agents are defined as the agents which helps the other element to get reduced and itself gets oxidized. These agents have a negative value of reduction potentials. The more the negative value, best is the reducing agent.

Reduction potentials of the following elements are:

Ag^+:0.80V\\Cr^{3+}:-0.74V\\Sn^{2+}:-0.14V\\Na^+:-2.71V

From the given reduction potentials, the best oxidizing agent is Ag^+ and the best reducing agent is Na^+

Order in the decreasing oxidizing agent ability of the species is Ag^+>Sn^{2+}>Cr^{3+}>Na^+

swat323 years ago
3 0

From best oxidizing agent to best reducing agent : <u>Ag⁺, Sn²⁺, Cr³⁺, Na⁺</u>

<h3>Further explanation</h3>

The oxidation-reduction reaction or abbreviated as Redox is a chemical reaction in which there is a change in oxidation number

3 basic theories explain this Redox concept:

  • 1. Binding / release of oxygen

The oxidation reaction is the binding of a substance with oxygen. (O₂)

For example:

2SO₂ + O₂ ----> 2SO₃

The reduction reaction is the release of oxygen from a substance.

For example:

2CuO → 2Cu + O₂

  • 2. Electron release / binding reaction

Oxidation is an electron release event

Example:

2F ---> 2Fe³⁺ + 6e⁻

The reduction is an electron capture event

Example:

3O₂ + 6e⁻ ---> 3O²⁻

  • 3. The reaction of addition / reduction of oxidation number

Oxidation is an increase  in oxidation number, while reduction is a decrease in oxidation number.

In the redox reaction, it is also known

Reducing agents are substances that experience oxidation

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series

Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing  agent

So that the metal located on the left can push the metal on the right in the redox reaction

From the ion ion below:

 Ag⁺ ;Cr³⁺ ;Sn²⁺; Na⁺

If we sort according to the voltaic series: (from left to right)

Na, Cr, Sn, Ag

Then:

Na, the most reactive, strong reducing agent

Ag, less reactive, strong oxidizing agents

So that the order from best oxidizing agent to best reducing agent.

Ag⁺, Sn²⁺, Cr³⁺, Na⁺

<h3>Learn more </h3>

an oxidation-reduction reaction

ainly.com/question/2973661

a reducing agent during a redox reaction

brainly.com/question/2890416

loses electrons in a chemical reaction

brainly.com/question/2278247

Keywords: reduction, oxidation

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Answer:

Multiply the number of moles in the product by the molecular weight of the product to determine the theoretical yield.

Explanation:

For example:

If you created 0.5 moles of Aluminium Oxide the molecular weight of Aluminium Oxide is 101.96g/mole, so you would get 50.98g as the theoretical yield.

So multiply,..

101.96x0.5= 50.98

This is the correct way to calculate the theoretical yield

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3 years ago
When gases dissolve in gases or when liquids and gases dissolve in liquids, _________eventually spreads the particles evenly thr
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When gases dissolve in gases or when liquids and gases dissolve in liquids, particles movement eventually spreads the particles evenly throughout the solvent resulting in a homogeneous mixture.​

Explanation:

When gases dissolve in gases or when liquids and gases dissolve in liquids, particle movement eventually spreads the particles evenly throughout the solvent resulting in a homogeneous mixture.​

Solid particles do not dissolve easily like liquids and gases dissolve. Solid particles when dissolved in solid the particles moves very little. After getting heated and becomes molten then they get mixed.

But in the liquids and gases atoms moves and the particles get eventually spread and also get mixed after cooled.

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3 years ago
How many moles of oxygen gas can 0.882 mol of hydrogen peroxide produce if decomposition is complete? 2H2O2 (l) → 2H2O(l) + O2(g
andreyandreev [35.5K]
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5 0
3 years ago
Read 2 more answers
A ball is equipped with a speedometer and launched straight upward. The speedometer reading four seconds after launch is shown a
Andrew [12]

Answer:

Question 1: <u>1 s after the motion starts</u>

Question 2: <u>0 (just when the motion starts)</u>

Explanation:

You will need to work with approximates values because the precision of the speedometers is low and you are requested to find approximate times.

<u>1. From the speedometer shown at the right.</u>

You can obtain how long the ball has been falling from the highest altitute it reached using the speed of 10 m/s shown by the speedometer at the right.

  • Free fall equation: Vf = Vo - gt

  • Vo = 0 ⇒ Vf = gt ⇒ t = Vf / g

For this problem, I recommend to work with a rough estimate of g: g = 10 m/s² ( I will tell you why soon)/

  • t = [10 m/s] / [10 m/s²] = 1 s

That is the time falling. Since four seconds after launch have elapsed, the upward time was 3 seconds. This will let you to calculate the launching speed.

<u>2. Time when the speedometer displays a reading of 20 m/s</u>

First, calculate the launching speed:

  • Vf = Vo - gt

Since the ball was 3 seconds going upward and the speed at the maximum altitude is 0 you get:

  • 0 = Vo - gt

   

  • Vo = gt = 10 m/s² × 3 s = 30 m/s

Now, use the initial velocity to calculate when the ball is going upward with the speedometer reading is 20 m/s

  • 20 m/s = 30 m/s - 10 m/s² × t

  • t = [ 30 m/s - 20 m/s] / [10 m/s²] = 1 s

Thus, the first answer is t = 1 s.

<u />

<u>3. Time when the speedometer displays a reading of 30 m/s</u>

This is the same speec estimated for the launching: 30 m/s.

So, this reading corresponds to the moment when the ball was launched.

Thus time is 0, i.e. it is the same instant of the launch.

If you had worked with g = 9.80 m/s², the time had been negative. This is due to the precision of the instruments.

That is why I recommended to work with g = 10 m/s².

6 0
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attashe74 [19]

Answer:

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Explanation:

We can use the <em>Ideal Gas Law</em> to calculate the individual gas pressure.

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Data:   n = 1.7 × 10⁶ mol

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T = 22 °C

V = 2.5 × 10⁷ L

Calculations:

(a) <em>Change the temperature to kelvins </em>

T = (22 + 273.15) K

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(b) Calculate the pressure

p = (1.7 × 10⁶ × 0.083 14 × 295.15)/(2.5× 10⁷)

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