Answer:
The new pressure is 1,65 atm
Explanation:
We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T.
(P1xV1)/T1= (P2xV2)/T2
(1,23atmx 8,46L)/267 K = (P2 x 6,98L)/ 295K
0,039 atmx L/K = (P2 x 6,98L)/ 295K
P2=(0,039 atmx L/K)x 295K/6,98L =1,65 atm
Answer:
As we are not provided with ¹H-NMR spectrum therefore we can not conclude a single result for the minor chlorination of propane with Molecular formula C₃H₆Cl₂.
Hence, we will draw all the possible isomers with molecular formula C₃H₆Cl₂ and predict the ¹H-NMR spectrum for each of them separately.
Below is the structures of possible minor products and the NMR spectrum respectively.
Possible Product A:
If the minor product formed is 2,2-Dichloropropane then it will give only one singlet peak in NMR spectrum.
Possible Product B:
If the minor product is 1,1-Dichloropropane then it will exhibit two triplets and one multiplet as shown in figure.
Possible Product C:
If the minor product is 1,2-Dichloropropane then it will give four peaks in NMR. The extra peak is formed due to two enantiomers about the chiral carbon.
Possible Product D:
If the minor product is 1,3-Dichloropropane then it will exhibit one triplet and one quintet signal as shown in figure.
There are
A. 6 significant figures
B.5 sig figs
C.2 sig figs
D.5 sig figs
<h2>
<u>Relationship between predator and prey in a balanced ecosystem.</u></h2>
Predators grow along with their victims. Over time, prey animals are now developing and avoiding themselves to get eaten by their predators. Such tactics and modifications can take many forms that make their work easier, including disguise, mimicry, defense mechanisms, flexibility, distance, habits and even tool use.
Though fact an equilibrium appears to occur within an ecosystem between predators and prey, there are several factors which affect it, including the birth and death rates of predators and preys.
Answer:
The standard change in free energy for the reaction = - 437.5 kj/mole
Explanation:
The standard change in free energy for the reaction:
4 KClO₃ (s) → 3 KClO₄(s) + KCl(s)
Given that ΔGf(KClO3(s)) = -290.9 kJ/mol;
ΔGf(KClO4(s)) = -300.4 kJ/mol;
ΔGf(KCl(s)) = -409 kJ/mol
According to Hess's law
ΔGr (Free energy change of reaction)= ∑(Product free energy - reactant free energy)
⇒ ΔGr⁰ = {3 x (-300.4) + (-409)} - {3 x (- 290.9)}
= - 901.2 - 409 + 872.7
= - 437.5 kj/mole
