Answer:
0.0984mol of F2
Explanation:
The equation for the reaction is given below:
Kr + F2 → KrF2
Let us convert 12g of KrF2 to mole. This is illustrated below
Molar Mass of KrF2 = 84 + (2x19) = 84 + 38 = 122g/mol
Mass of KrF2 = 12g
Number of mole = Mass /Molar Mass
Number of mole of KrF2 = 12/122 = 0.0984mol
From the equation,
1mole of F2 produced 1mole of KrF2.
Therefore 0.0984mol of F2 will produce 0.0984mol of KrF2
Answer:
Solution A that will form a precipitate with Ksp = 2.3 x 10−4
Explanation:
Li₃PO₄ ⇄ 3 Li⁺(aq) + PO₄³⁻(aq)
3S S
Where S = Solubility(mole/lit) and Ksp = Solubility product
⇒ Ksp = (3S)³ x (S)
⇒ 27S⁴ = 2.3x10−4
⇒ S = 0.05 mol/lit
Concentration of Li₃PO₄ precipitate = 0.05
<u>Solution A </u>
0.500 lit of a 0.3 molar LiNO₃ contains 0.5 x 0.3 = 0.15 mole
0.4 lit of a 0.2 molar Na₃PO₄ contains = 3 x 0.4 x 0.2 = 0.24 mole
3 LiNO₃ + Na₃PO₄ → 3 NaNO₃ + Li₃PO₄
(Mole/Stoichiometry)
= 0.05 = 0.24
Since from (Mole/Stoichiometry) ratio we can conclude that LiNO₃ is limiting reagent.
So concentration of Li₃PO₄ is equal to 0.05.
Answer:
4 grams
Explanation:
A = A₀e^⁻kt
A₀ = 125.0 grams
k= 0.693/t(1/2) = (0.693/68.8) yrs⁻¹ = 0.01 yrs⁻¹
t = 344.0 years
A = 125.0g·[e^-(0.01yrs⁻¹)(344.0yrs)] = 125(0.032)grams = 4.000g (4 sog. figs. based on A₀ = 125.0 grams)
Answer: mass
Explanation: the protons and neutrons make up the nucleus and nearly the entire mass of the atom
Explanation:
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