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3 years ago

15

Inga lives 3 miles more than twice as far from school as brent does . If Brent lives (b) miles from school, then inga lives _? m

iles from school. (explain)

1 answer:

finlep [7]3 years ago

5 0

Brent lives b miles from the school.
Inga lives 3 miles more then twice as far as Brent.
2b + 3.

Inga lives (2b + 3) miles from school.

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A jar contains a 8 blue marbles, 12 red marble, and 3 yellow marbles. What is the probability of drawing a blue marble, placing

chubhunter [2.5K]

I'm not for sure but it could be 24/529 ???????????

If there are answer choices then put this one. Otherwise I really don't know

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3 years ago

(8.4x + 2.9) + (-3.7x + 5).

konstantin123 [22]

Answer:

10

Step-by-step explanation:

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4 years ago

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

3 years ago

Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5

hjlf

The rule of geometric sequence is ⇒⇒⇒ a * r^(n-1)
Where a is the first term and r is the common ratio
for the given sequence √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5

5 0

3 years ago

According to a certain news poll, 71% agreed that it should be the government's responsibility to provide a decent standard of l

finlep [7]

Answer:

0.3157

Step-by-step explanation:

Given that according to a certain news poll, 71% agreed that it should be the government's responsibility to provide a decent standard of living for the elderly,

Let A be the event that it should be the government's responsibility to provide a decent standard of living for the elderly, and B the event that it would be a good idea to invest part of their Social Security taxes on their own

P(B) = 41%=0.41

A and B are independent

Hence P(both)= $0.77(0.41) = 0.3157\\$

the probability that a person agreed with both propositions

= Probability for both A and B

= P(A) P(B) since A and B are independent

= 0.3157

3 0

3 years ago