The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

In this case, we have
<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> ) ==> d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )
<em>y(t)</em> = 5 - 2<em>t</em> ==> d<em>y</em>/d<em>t</em> = -2
and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then





Given:
Consider the below figure attached with this question.
The linear equation is:

To find:
The values to complete the table of ordered pairs for the given linear equation.
Solution:
We have,

Substituting
in the given equation, we get



So, the value for first blank is -8.
Substituting
in the given equation, we get




So, the value for second blank is 3.
Substituting
in the given equation, we get



So, the value for third blank is -4.
Therefore, the required complete table is:
x y
0 -8
3 -2
2 -4
The value decimal point is changing going to the right as you divide a number by 10.
For example
=> 2000.3 / 10
notice the decimal point
=> 200.013, the value of decimal numbers increases as the value of whole number decreases.Let’s divide again
=> 200.013 / 10
=> 20.0013 , now we already have 4 digits in our decimals.
So, simply as we divide the given number by 10, the decimal point moves to the left making the value of whole number decreases and making the number of digits of decimal increase.
Answer:
- increasing: (-∞, 0)
- decreasing: (0, ∞)
Step-by-step explanation:
The function goes up to the right until it gets to the vertex at x=0. Then it goes down to the right. That is, it is ...
increasing from -∞ to 0 (not including 0)
decreasing from 0 to +∞ (not including 0)
_____
At x=0, the function is neither increasing nor decreasing, so x=0 is not part of either interval.
As you can see in the picture above, there are six faces of a rectangular prism; two are formed with dimensions width and height, two are formed by the dimensions length and width, and two are formed by the dimensions length and height. So, if you know the length, width, and height of the rectangular prism, then the formula for the surface area is
=(2⋅ℎ⋅ℎ)+(2⋅ℎ⋅ℎℎ)+(2⋅ℎ⋅ℎℎ)