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Deffense [45]
4 years ago
11

A flask contains 2.0 mol of He gas at 25°C and 1.00 atm. How much He gas, in grams, must be added to increase the pressure to 2.

00 atm at constant temperature and volume?
Chemistry
1 answer:
katrin [286]4 years ago
3 0

Answer:

Mass of He required = 8.0 g

Explanation:

Given,

Initial moles of He = 2.0 mol

Initial pressure = 1.00 atm

final pressure = 2.00 atm

Ideal gas equation,

PV = nRT

As V, R and T are constant

So, \frac{P_1}{P_2} =\frac{n_1}{n_2}

\frac{1.00 atm}{2.00 atm} =\frac{2.0}{n_2}\\n_2=\frac{2.0\times 2.00}{1.00} \\n_2=4.0 mol

Molar mass of He = 4.00 g/mol

No. of moles of He needs to be added = 4.0 - 2.0 = 2.0 mol

Mass = No. of mole × Molar mass

         = 2.0 × 4.0

          = 8.0 g

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