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Yanka [14]
3 years ago
12

Which of the following is(are) the reason(s) metals are good conductors of heat and electricity? Select all that apply

Chemistry
1 answer:
Mariana [72]3 years ago
5 0

Answer: The question is incomplete and the options are not given but here are the options.

a. Metals can absorb more heat flow than other elements before damage occurs.

b. Particles of metallic structure begin to vibrate faster as they absorb energy.

c. Metals have a larger number of freely moving electrons.

d.Metals have high densities.

e. Metals have high melting points.

The correct options are c,d and e.

c. Metals have a larger number of freely moving electrons.

d.Metals have high densities.

e. Metals have high melting points.

The correct options are c,d and e.

Explanation:

Metals are real good conductor of heat because of the following;

Metals have larger number of freely moving electrons and these electrons move in random motion that is they are not stable, they from from place to place. Current generated in a direction is destroyed by current produced in another direction also.

Metals have high densities which is because their crystal lattice are packed very tight in the metallic structure making the metal bond to be stronger and conduct heat.

Metals have high melting point because that have a very strong metallic bond and this bond require a lot of energy to break, therefore making it to conduct heat and electricity.

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During the pyramid-building era the ancient
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Copper is formed when aluminum reacts with copper (II) sulfate in a single-replacement reaction. How many moles of copper can be
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Answer:

The answer to your question is the limiting reactant is CuSO₄ and 0.975 moles of Cu were obtained

Explanation:

moles of Copper = ?

mass of Aluminum = 29 g

mass of CuSO₄ = 156 g

Limiting reactant = ?

Balanced Chemical reaction

                  3 CuSO₄   +  2 Al   ⇒   3 Cu   +  Al₂(SO₄)₃

Calculate the moles of reactants

CuSO₄ = 64 + 32 + (16 x 4) = 160g

Al = 27 g

                160 g of CuSO₄  ----------------- 1 mol

                156 g                   -----------------  x

                      x = (156 x 1) / 160

                      x = 0.975 moles

               27 g of Al -------------------------- 1 mol

               29 g of Al -------------------------- x

                x = (29 x 1)/27

                x = 1.07 moles

Calculate proportions to find the limiting reactant

Theoretical     3 moles CuSO₄/2 moles Al = 1.5 moles

Experimental  0.975 moles CuSO₄/1.07 moles = 0.91

The experimental proportion was lower than the theoretical proportion that means that the limiting reactant is CuSO₄.      

                    3 moles of CuSO₄ ------------------ 3 moles of Cu

                 0.975 moles of CuSO₄ ---------------  x

                         x = (0.975 x 3)/3

                        x = 0.975 moles of Cu were obtained.        

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