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Simora [160]
3 years ago
10

Divya is organizing a training for two different seminars, one for teachers and one for mechanics. She has a total of 132 pens a

nd 87 pads of paper. If each of the teachers need 3 pads of paper and 5 pens, and each of the mechanics needs 1 pad of paper and 2 pens, how many teachers and mechanics can she have at the conventions?

Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Step-by-step explanation:

Below is an attachment containing the solution.

You might be interested in
F(x)= 2x^3- x^2 +x+ 1 is divided by 2x +1.
ololo11 [35]

Answer:

Step-by-step explanation:

               x^2

           --------------------------------------------------

2x + 1  /  2x^3     -     x^2    +      x      +    1

               2x^3    +    x^2

              -----------------------

                                    0 + x + 1

                                        x + 1

The quotient is  x^2 + ------------

                                       2x + 1

8 0
2 years ago
Nina can ride her bike 63,000 feet in 3,400 seconds, and Sophia can ride her bike 10 miles in 1 hour. What is Nina’s rate in mil
miss Akunina [59]

Answer:

Step-by-step explanation:

u need to multiply.

4 0
3 years ago
Show 240.149 in two different ways
Ksenya-84 [330]
240 149/1000 fraction and 240.149 in decimal
5 0
3 years ago
Read 2 more answers
A company with a fleet of 150 cars found that the emissions systems of only 4 out of the 32 they tested failed to meet pollution
lidiya [134]

Answer:

Yes

Step-by-step explanation:

First, we need to find how many cars out of the entire fleet fail the test

4/32 = x/150

Cross multiply to find x

32x = 150(4)

32x = 600

32x/32 = 600/32

x = 18.75

I'll round it to 19. So 19 out of 150 cars fail the test. Find the percentage of this and compare it to the 30% estimate

19 /150 = 0.127

0.127(100) = 12.7%

12.7% is obviously lower than 30% so yes it is strong evidence the percentage of the fleet out of compliance is different from their initial thought

8 0
3 years ago
Your lungs hold about 4.5 liters of air after you inhale and about 3.5 liters of air after you exhale. If you take 6 breaths eve
ser-zykov [4K]

Answer:

A(t)=0.5cos(12\pi\cdot t)+4

Step-by-step explanation:

<u>Function Modeling</u>

Since the air in the lungs goes periodically from a minimum value to a maximum value, we can simulate its behavior as a sinusoid. Selecting a sine or a cosine will depend on the initial condition we'll assume since the question doesn't provide one. We'll set the initial state when the lungs are at maximum air content. The sinusoid that starts from maximum is the cosine, so our model is

A(t)=A_ocos(wt)+M

Where Ao is the amplitude of the oscillation, w is the angular frequency and M is the midline or y-displacement of the wave.

The values of A run from a min of 3.5 to a max of 4.5. That gives us twice the amplitude, thus

\displaystyle A_o=\frac{4.5-3.5}{2}=0.5

The vertical displacement or midline can be found as the shift from the center value:

\displaystyle M=\frac{4.5+3.5}{2}=4

We also know the cycle repeats 6 times per minute. If the time is expressed in minutes, then the frequency is f=6

Knowing that

w=2\pi f

Then

w=12\pi

The model is

\boxed{A(t)=0.5cos(12\pi\cdot t)+4}

where t is expressed in minutes

7 0
3 years ago
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