Answer:
![2a^3b^2\sqrt[3]{3a}](https://tex.z-dn.net/?f=2a%5E3b%5E2%5Csqrt%5B3%5D%7B3a%7D)
Step-by-step explanation:
Use the following rules for exponents:
![a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x](https://tex.z-dn.net/?f=a%5Em%2Aa%5En%3Da%5E%7Bm%2Bn%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%5E3%7D%3Dx)
Simplify 24. Find two factors of 24, one of which should be a perfect cube:

Insert:
![\sqrt[3]{2^3*3a^{10}b^6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%5E3%2A3a%5E%7B10%7Db%5E6%7D)
Now split the exponents. Split 10 into as many 3's as possible:

Insert as exponents:
![\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%5E3%2A3%2Aa%5E3%2Aa%5E3%2Aa%5E3%2Aa%5E1%2Ab%5E6%7D)
Split 6 into as many 3's as possible:

Insert as exponents:
![\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%5E3%2A3%2Aa%5E3%2Aa%5E3%2Aa%5E3%2Aa%5E1%2Ab%5E3%2Ab%5E3%7D)
Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):
![2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B3%2Aa%5E3%2Aa%5E3%2Aa%5E3%2Aa%5E1%2Ab%5E3%2Ab%5E3%7D%5C%5C%5C%5C%5C%5C2%2Aa%2Aa%2Aa%5Csqrt%5B3%5D%7B3%2Aa%5E1%2Ab%5E3%2Ab%5E3%7D%5C%5C%5C%5C%5C%5C2%2Aa%2Aa%2Aa%2Ab%2Ab%5Csqrt%5B3%5D%7B3%2Aa%5E1%7D)
Simplify:
![2a^3b^2\sqrt[3]{3a}](https://tex.z-dn.net/?f=2a%5E3b%5E2%5Csqrt%5B3%5D%7B3a%7D)
:Done
Answer:
See Below
Step-by-step explanation:
1) 180 ft / 6 sec
To find a unit rate, you need to have a denominator of 1 and to to do that, you can divide the numerator and denominator by the same number, in this case: 6.
30 ft / 1 sec
2) 86 mi / 5 hr
Same as above^(except dividing by 5)
17.2 mi / 1 hr
3) 83 mi / 5 hr
Same as above^^
16.6 mi / 1 hr
We can rewrite this as: 16.6 mph
4) 93 mi / 5 hr
Same as above^^^
18.6 mi / 1 hr
5) 150 mi / 4 hr
Same as above^^^^
37.5 mi / 1 hr
We can rewrite this as: 37.5 mph
The ratio of building heights will be the same as the ratio of shadow lengths.
(taller building)/(shorter building) = (longer shadow)/(shorter shadow)
(taller building)/(84 ft) = (110 ft)/(46 ft) . . . . . . fill in the given numbers
(taller building) = (84 ft)*(110/46) ≈ 200.9 ft . . multiply by 84 ft, evaluate
The appropriate selection is
D) 200.9 ft
Answer:
$14
Step-by-step explanation:
$20 minus the $6 she came back with equals $14, which is what she spent.
(20-6=14)