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Elza [17]
4 years ago
14

When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less dam

age. In one such accident, a 1850 kg car traveling to the right at 1.50 m/s collides with a 1400 kg car going to the left at 1.10 m/s . Measurements show that the heavier car's speed just after the collision was 0.250 m/s in its original direction. You can ignore any road friction during the collision.
What was the speed of the lighter car just after the collision?
Physics
1 answer:
Lesechka [4]4 years ago
4 0

Answer:

0.55 m/s

Explanation:

Parameters given:

Mass of lighter car, m = 1400 kg

Mass of heavier car, M = 1850 kg

Initial speed of lighter car, u = -1.10 m/s (since it's moving to the left)

Initial speed of heavier car, U = 1.5 m/s

Final sped of heavier car, V = 0.25 m/s

Using the principle of conservation of momentum, total initial momentum is equal to total final momentum:

m*u + M*U = m*v + M*V

Inputting the values:

(1400 * -1.1) + (1850 * 1.5) = (1400 * v) + (1850 * 0.25)

-1540 + 2775 = 1400v + 462.5

1235 = 1400v + 462.5

1400v = 772.5

v = 772.5/1400

v = 0.55 m/s

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Answer:

  C.  greater than D, but less than 2D

Explanation:

The amount of potential energy in the system is a function of the compression of the spring. That is the same for both masses.

The potential energy is transferred to kinetic energy when the spring is released. The kinetic energy is jointly proportional to the mass and the square of the velocity. That is, the velocity is inversely proportional to the square root of the mass, for the same kinetic energy.

The horizontal distance traveled will be proportional to the launch velocity. So a halving of the mass will increase the velocity by a factor of ...

  v2 = v1·√(1/(1/2)) = v1·√2

This means the second mass will land at a distance of about D√2, a value ...

  greater than D but less than 2D.

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3 years ago
Calculate the average speed of spacecraft orbiting mars
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That completely depends on the size of the orbit. Similarly at Earth, a TV satellite takes 1 day for an orbit, but the Moon takes 27.3 days.
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3 years ago
You have decided to study the effect of loud noise on plant growth. You put one plant in a quiet room and the other plant in you
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4 0
4 years ago
Read 2 more answers
A hoop and a solid disc are relased from rest
Murljashka [212]

Answer:

1) The hoop and a solid disc rolling without slipping down an incline plane.

Their final velocities are proportional to their moment of inertia.

The condition for moment of inertia: v = ωR

We will use conservation of energy.

<u>For the hoop:</u>

K_1 + U_1 = K_2 + U_2\\0 + m_hgh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}I\omega_h^2 + 0

They are released from rest, so their initial kinetic energy is zero. And when they reach the bottom, their final potential energy is also zero.

The moment of inertia of a hoop is

I_h = m_hR^2

Let's continue with the energy equations:

m_h gh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}(m_hR^2)(\frac{v_h^2}{R^2})\\m_hgh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}m_hv_h^2\\m_hgh = m_hv_h^2\\v_h = \sqrt{gh}

Similarly <u>for the solid disk</u> with a moment of inertia of (1/2)mR^2:

K_1 + U_1 = K_2 + U_2\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{2}I_d\omega_d^2\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{2}(\frac{1}{2}m_dR^2)(\frac{v_d^2}{R^2})\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{4}m_dv_d^2\\m_dgh = \frac{3}{4}m_dv_d^2\\v_d = \sqrt{\frac{4gh}{3}}

Comparing the final velocities, we can conclude that the solid disk reaches the bottom first.

2) The angular acceleration of the pebble is equal to the angular acceleration of the tire, since they stuck together. We can deduce the angular acceleration of the tire from the linear acceleration of the bicycle.

The kinematics equations states that

v = v_0 + at\\4.47 = 0 + 2a\\a = 2.235 ~m/s^2

where a is the linear acceleration.

The relation with the angular and linear acceleration is

a = \alpha R

where R is the radius of the tire. Since it is not given in the question, we will leave it as R.

The angular acceleration of the small pebble is

\alpha = 2.235/R ~m/s^2

4 0
4 years ago
Read 2 more answers
Buckets and a Pulley Two buckets of sand hang from opposite ends of a rope that passes over an ideal pulley. One bucket is full
marin [14]

Answer:

A: T = 120 N

B: T = 88.42 N

C: T = 70 N

Explanation:

Part A:

Since, the lighter bucket is supported by my had. So, the only unbalanced force in the system is the weight of heavier bucket. Hence, the tension in rope will be equal to the weight of heavier bucket.

<u>T = 120 N</u>

<u></u>

Part B:

This is the case where, two masses hang vertically on both sides of the pulley. To find the tension in such case we have the formula:

T = (2 m₁m₂g)/(m₁+m₂)

where,

m₁ = mass of heavier object = W₁/g = (120 N)/(9.8 m/s²) = 12.24 kg

m₁ = mass of lighter object = W₂/g = (70 N)/(9.8 m/s²) = 7.14 kg

g = 9.8 m/s²

Therefore,

T = [(2)(12.24 kg)(7.14 kg)(9.8 m/s²)]/(12.24kg + 7.14 kg)

T = 1713.6 N.kg/19.38 kg

<u>T = 88.42 N</u>

<u></u>

Part C:

Since, the heavier bucket is on ground. So, its weight is balanced by the normal reaction of the ground. The only unbalanced force in the system is the weight of lighter bucket. Hence, the tension in rope will be equal to the weight of lighter bucket.

<u>T = 70 N</u>

4 0
3 years ago
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