All categories

2 years ago

The circumference of the target above is 6,895.4400000000 mm.

Mathematics

1 answer:

Sergio039 [100]2 years ago

4 0

Diameter of the target is 2196 mm

Step-by-step explanation:

We are given Circumference of target = 6,895.4400000000 mm.

We need to find the diameter of target.

The formula used is:

$C= 2\pi r$

Putting values:

$C=2\pi r\\6,895.4400000000=2*3.14*r\\6,895.4400000000=6.28*r\\r=\frac{6,895.4400000000}{6.28} \\r=1098\,\,mm \\$

We know that $Diameter = 2*radius$

So, Finding Diameter:

$Diameter = 2*radius\\Diameter = 2*1098\\Diameter = 2196\,\,mm$

So, Diameter of the target is 2196 mm

Keywords: Circumference

Learn more about Circumference at:

#learnwithBrainly

You might be interested in

If two polynomial equations have real solutions, then will the equation that is the result of adding, subtracting, or multiplyin

kirill115 [55]

No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.

Consider polynomial equations x^2 = 3 and x^2 = 1.

Obviously they have real solutions.

Subtract the two polynomial equations:

(x^2 - x^2) = (3 - 1)

0 = 2...

We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.

Obviously 0 = 2 has no real solution.

3 0

2 years ago

Hii whats your name heehee

Roman55 [17]

Answer:

Kimberly

Step-by-step explanation:

My mother gave me the name

5 0

1 year ago

Find the circumference of a circle that has a radius of 36 inches

SVEN [57.7K]

I think that the answer is 226.194 inches

7 0

2 years ago

A certain radioactive isotope has leaked into a small stream. Three hundred days after the leak, 3% of the original amount of t

sesenic [268]

If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days

6 0

3 years ago

Using a table of values, determine the solution to the equation below to the nearest fourth of a unit. 2^x=1-3^x

Greeley [361]

Answer:

Option (1)

Step-by-step explanation:

Given equation is,

$2^x=1-3^x$

To determine the solution of the equation we will substitute the values of 'x' given in the options,

Option (1)

For x = -0.75

$2^{-0.75}=1-3^{-0.75}$

0.59 = 1 - 0.44

0.59 = 0.56

Since, values on both the sides are approximately same.

Therefore, x = -0.75 will be the answer.

Option (2)

For x = -1.25

$2^{-1.25}=1-3^{-1.25}$

0.42 = 1 - 0.25

0.42 = 0.75

Which is not true.

Therefore, x = -1.25 is not the answer.

Option (3)

For x = 0.75

$2^{0.75}=1-3^{0.75}$

1.68 = 1 - 2.28

1.68 = -1.28

Which is not true.

Therefore, x = 0.75 is not the answer.

Option (4)

For x = 1.25

$2^{1.25}=1-3^{1.25}$

2.38 = 1 - 3.95

2.38 = -2.95

It's not true.

Therefore, x = 1.25 is not the answer.

6 0

2 years ago