Answer:
Silver
Explanation:
What mass of copper was discharge at the cathode in a cell
The student's test average is : 0.92
Total score obtained = 369
Number of tests = 4
Since Each test is exactly 100 points ;
The total score obtainable is (100 × 4) = 400
Average = score obtained / total score obtainable
Average = 369 / 400
Average = 0.9225
Average = 0.92
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Answer: The name of this Hydrate is magnesium sulphate monohydrate.
Explanation:
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
a) If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of = 87.0 g
Mass of = 13.0 g
Step 1 : convert given masses into moles
Moles of =
Moles of =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For =
For =
Hence the empirical formula is
Thus the name is magnesium sulphate monohydrate.
<span>Colligative properties are properties of solutions that depend on the number of molecules [or ions] in a given volume of solvent and not on the properties (e.g. size or mass) of the compound. Colligative properties include: lowering of vapor pressure; elevation of boiling point; depression of freezing point and osmotic pressure.</span>
Answer:
Volume of gold is 9.64 L
.
Explanation:
Given data:
Mass of gold = 85 g
Temperature = standard = 273 K
Pressure = standard = 1 atm
Volume of gold = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will calculate the number of moles of gold.
Number of moles = mass/molar mass
Number of moles = 85 g/ 197 g/mol
Number of moles = 0.43
1 atm × V = 0.43 mol ×0.0821 atm.L/ mol.K × 273 K
V = 9.64 atm.L / 1 atm
V = 9.64 L