Answer:
0.208mole of CO2
Explanation:
First, let us calculate the number of mole of HC3H3O2 present.
Molarity of HC3H3O2 = 0.833 mol/L
Volume = 25 mL = 25/100 = 0.25L
Mole =?
Mole = Molarity x Volume
Mole = 0.833 x 0.25
Mole of HC3H3O2 = 0.208mole
Now, we can easily find the number of mole of CO2 produce by doing the following:
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2
From the equation,
1mole of HC2H3O2 produced 1 mole of CO2.
Therefore, 0.208mole of HC2H3O2 will also produce 0.208mole of CO2
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Answer:calcium
Explanation: calcium is an alkaline earth metal,group 2 period 4
Answer:
300 kg
Explanation:
The give parameters obtained from a similar question are;
The mass of oseltamivir per capsule = 75 mg
The mass of oseltamivir required, <em>M</em>, is given as follows;
M = The mass of oseltamivir per capsule × The mass taken per person per day × 5 days × The number of people in the city
M = 0.75 mg/capsule × 2 capsule/(day·person) × 5 days × 400,000 people
M = 300,000,000 mg = 300 kg
