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3 years ago

Determine if each compound shown is soluble or insoluble. cu(oh)2

Chemistry

1 answer:

vredina [299]3 years ago

4 0

We have to determine if the given compound is soluble or insoluble in water.

The given compound is copper (II) hydroxide, $Cu(OH)_{2}$ . According to the solubility rules the hydroxides of all metal ions are insoluble except that of ammonium and the alkali metal ions. So copper(II) hydroxide will be insoluble in water. In aqueous solution, copper (II) hydroxide would exist as a sparingly soluble compound in which the undissociated compound remains in equilibrium with the ions $Cu^{2+}$ and $OH^{-}$ . The equilibrium would remain mostly towards undissociated form.

$Cu(OH)_{2}(s)Cu^{2+}(aq)+2OH^{-}(aq)$

Therefore, $Cu(OH)_{2}$ is insoluble in water.

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The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of 8.1% per day. f

Elanso [62]

The general equation for radioactive decay is;
N = N₀e^(-λt)
x - decay constant (λ) - rate of decay
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N - amount remaining after t days , since we are calculating the half life, amount of time it takes for the substance to to be half its original value, its N₀/2
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substituting the values
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5 0

3 years ago

c3H8 + 5O2 = 3CO2 + 4H2O When 44.0 grams of propane (C3H8) under goes complete combustion, how many grams of water will be produ

Umnica [9.8K]

<u>Answer:</u> 72 grams of water will be produced.

<u>Explanation:</u>

To calculate the number of moles, we use the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

Mass of propane = 44 grams

Molar mass of propane = 44 grams

Putting values in above equation, we get:

$\text{moles of propane}=\frac{44g}{44g/mol}=1mole$

For the reaction of combustion reaction of propane, the equation follows:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

By Stoichiometry of the reaction,

1 mole of propane produces 4 moles of water.

So, 1 mole of propane will produce = $\frac{1}{1}\times 4=4moles$ of water.

Now, to calculate the amount of water, we use equation 1, we get:

Molar mass of water = 18 g/mol

$4mol=\frac{\text{Mass of water}}{18g/mol}$

Mass of water produced = 72 grams

Hence, 72 grams of water will be produced.

6 0

3 years ago

A metal cylinder has a mass of 128g. When the cylinder is submerged into water, it displaces 424ml of water. Calculate the speci

Colt1911 [192]

First, we will need to find the density of the object, take the mass and divide it by the dispplaced water:
128/424 = 0.302 grams/milliliters
Convert that to kg/m3
We get: 302kg/m3
Divide that to the density of water: 1000kg/m3
302/1000 = 0.302
(thats a pretty darn light weighted metal)

7 0

3 years ago