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3 years ago

Determine if each compound shown is soluble or insoluble. cu(oh)2

Chemistry

1 answer:

vredina [299]3 years ago

4 0

We have to determine if the given compound is soluble or insoluble in water.

The given compound is copper (II) hydroxide, $Cu(OH)_{2}$ . According to the solubility rules the hydroxides of all metal ions are insoluble except that of ammonium and the alkali metal ions. So copper(II) hydroxide will be insoluble in water. In aqueous solution, copper (II) hydroxide would exist as a sparingly soluble compound in which the undissociated compound remains in equilibrium with the ions $Cu^{2+}$ and $OH^{-}$ . The equilibrium would remain mostly towards undissociated form.

$Cu(OH)_{2}(s)Cu^{2+}(aq)+2OH^{-}(aq)$

Therefore, $Cu(OH)_{2}$ is insoluble in water.

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The electron configuration of a neutral atom is 1s22s22p63s2. Write a complete set of quantum numbers for each of the electrons.

Pavlova-9 [17]

Answer:

The four quantum number for each electron will be:

$1s^{2}$

$n=1;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}$

$2s^{2}$

$n=2;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}$

$2p^{6}$

$n=1;l=1;\\m=+1,0.-1 \\s=+\frac{1}{2}/-\frac{1}{2}$

$3s^{2}$

$n=3;l=0;m=0;s=+\frac{1}{2}/-\frac{1}{2}$

Explanation:

As the element is neutral, the number of protons will be equal to number of electrons which will be the atomic number of the element.

Number of electrons =12

Atomic number = 12

Element : Magnesium

The principal shell is represented by "n"

i) For "s" subshell the value of l =0 (azimuthal quantum number) thus m (magnetic quantum number)= 0

The two electrons in s subshell will have either plus half or minus half spin quantum number

ii) for "p" subshell the value for l =1

thus m = 0 or +1 or -1

The two electrons in each orbital will have either plus half or minus half spin quantum number

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n(Na₂S)=n{Cd(NO₃)₂}=cv

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