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3 years ago

What is the mass of lead in 452 g PbCl2?

Chemistry

1 answer:

oksano4ka [1.4K]3 years ago

4 0

335.664 grams is the mass of lead in 452 grams of PbCl2.

Explanation:

Data given:

mass of lead in PbCl2 = 452 grams

mass of lead =?

atomic mass of PbCl2 = 278.1 grams/mole

atomic mass of Pb = 207.2 grams/mole

atomic mass of chlorine = 35.45 grams/mole

From the chemical formula of PbCl2 it is deduced that 1 mole of lead chloride contains 1 mole of Pb cation and 2 moles of chloride anion

number of moles of PbCl2 provided are:

number of moles = $\frac{mass}{atomic mass}$

number of moles = 1.62 moles of PbCl2 is provided

so when 1 mole of PbCl2 contains 1 mole of lead

then 1.62 moles of PbCl2 will have 1.62 moles of lead

mass = atomic mass x number of moles

mass of lead = 1.62 x 207.2

mass of lead = 335.664 grams

335.664 grams of lead is present in a sample of lead chloride having mass of 452 grams.

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Answer:

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Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $CH_4$ :-

Mass of $CH_4$ = 1.28 g

Molar mass of $CH_4$ = 16.04 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{1.28\ g}{16.04\ g/mol}$

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The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{10.1\ g}{31.998\ g/mol}$

$Moles_{O_2}= 0.3156\ mol$

According to the given reaction:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

1 mole of methane gas reacts with 2 moles of oxygen gas

0.0798 mole of methane gas reacts with 2*0.0798 moles of oxygen gas

Moles of oxygen gas = 0.1596 moles

Available moles of oxygen gas = 0.3156 moles

<u>Limiting reagent is the one which is present in small amount. Thus, $CH_4$ is limiting reagent. </u>

The formation of the product is governed by the limiting reagent. So,

1 mole of methane gas on reaction produces 1 mole of carbon dioxide.

0.0798 mole of methane gas on reaction produces 0.0798 mole of carbon dioxide.

Mole of carbon dioxide = 0.0798 mole

Molar mass of carbon dioxide = 44.01 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.0798\ moles= \frac{Mass}{44.01\ g/mol}$

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