What is the mass of lead in 452 g PbCl2?
1 answer:
335.664 grams is the mass of lead in 452 grams of PbCl2.
Explanation:
Data given:
mass of lead in PbCl2 = 452 grams
mass of lead =?
atomic mass of PbCl2 = 278.1 grams/mole
atomic mass of Pb = 207.2 grams/mole
atomic mass of chlorine = 35.45 grams/mole
From the chemical formula of PbCl2 it is deduced that 1 mole of lead chloride contains 1 mole of Pb cation and 2 moles of chloride anion
number of moles of PbCl2 provided are:
number of moles =
number of moles = 1.62 moles of PbCl2 is provided
so when 1 mole of PbCl2 contains 1 mole of lead
then 1.62 moles of PbCl2 will have 1.62 moles of lead
mass = atomic mass x number of moles
mass of lead = 1.62 x 207.2
mass of lead = 335.664 grams
335.664 grams of lead is present in a sample of lead chloride having mass of 452 grams.
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Explanation:
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Mg(s) + N₂0(g) → MgO(s) + N₂(g)
has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .
<u>Answer:</u> The initial pH of the HCl solution is 3
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
1 mole of HCl produces 1 mole of ions and 1 mole of
ions
To calculate the pH of the solution, we use the equation:
We are given:
Putting values in above equation, we get:
Hence, the initial pH of the HCl solution is 3