What is the mass of lead in 452 g PbCl2?
1 answer:
335.664 grams is the mass of lead in 452 grams of PbCl2.
Explanation:
Data given:
mass of lead in PbCl2 = 452 grams
mass of lead =?
atomic mass of PbCl2 = 278.1 grams/mole
atomic mass of Pb = 207.2 grams/mole
atomic mass of chlorine = 35.45 grams/mole
From the chemical formula of PbCl2 it is deduced that 1 mole of lead chloride contains 1 mole of Pb cation and 2 moles of chloride anion
number of moles of PbCl2 provided are:
number of moles =
number of moles = 1.62 moles of PbCl2 is provided
so when 1 mole of PbCl2 contains 1 mole of lead
then 1.62 moles of PbCl2 will have 1.62 moles of lead
mass = atomic mass x number of moles
mass of lead = 1.62 x 207.2
mass of lead = 335.664 grams
335.664 grams of lead is present in a sample of lead chloride having mass of 452 grams.
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The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.
<em>"Your question is not complete, it seems to be missing the diagram of the emission spectrum"</em>
the diagram of the emission spectrum has been added.
<em>From the given</em><em> chart;</em>
The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m
The frequency of this emission is calculated as follows;
c = fλ
where;
- <em>c is the speed of light = 3 x 10⁸ m/s</em>
- <em>f is the frequency of the wave</em>
- <em>λ is the wavelength</em>
The energy of the emitted photon corresponding to the orange line is calculated as follows;
E = hf
where;
- <em>h is Planck's constant = 6.626 x 10⁻³⁴ Js</em>
<em />
E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)
E = 3.26 x 10⁻¹⁹ J.
Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.
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