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masya89 [10]
3 years ago
6

Differentiate Functions of Other Bases In Exercise, find the derivative of the function.

Mathematics
1 answer:
densk [106]3 years ago
7 0

Answer:

The derivative of the function is:

g'(x) = \frac{1}{1.6094x}

Step-by-step explanation:

If we have a function in the following format:

g(x) = \log_{a}{f(x)}

This function has the following derivative

g'(x) = \frac{f'(x)}{f(x)*\ln{a}}

In this problem, we have that:

g(x) = \log_{5}{x}

So f(x) = x, f'(x) = 1, a = 5

The derivative is

g'(x) = \frac{f'(x)}{f(x)*\ln{a}}

g'(x) = \frac{1}{x*\ln{5}}

g'(x) = \frac{1}{1.6094x}

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Answer:

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1st on is one solution

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Whats -3u + 5 if u=2​
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-1

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-3(2) = -6 + 5 = -1

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4 years ago
What are the first 300 digits of pie first answer is brainiest
Gelneren [198K]

Answer:

3.

141592653589793238462643383279502884197169399375105

82097494459230781640628620899862803482534211706798

21480865132823066470938446095505822317253594081284

81117450284102701938521105559644622948954930381964

42881097566593344612847564823378678316527120190914

5648566923460348610454326648213393607260249141273

Step-by-step explanation:

:)

6 0
3 years ago
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A projectile is fired upward from the ground with an initial velocity of 300 feet per second. Neglecting air resistance, the hei
levacccp [35]

Answer: The polynomial that describes the projectile's height is:

P(t) = - ­16t*2 + 300t

For t = 1 second we have:

P(1) = - 16*1^2 + 300*1

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The height of the projectile after 1 second is 284 feet.

Step-by-step explanation:

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