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masya89 [10]
3 years ago
6

Differentiate Functions of Other Bases In Exercise, find the derivative of the function.

Mathematics
1 answer:
densk [106]3 years ago
7 0

Answer:

The derivative of the function is:

g'(x) = \frac{1}{1.6094x}

Step-by-step explanation:

If we have a function in the following format:

g(x) = \log_{a}{f(x)}

This function has the following derivative

g'(x) = \frac{f'(x)}{f(x)*\ln{a}}

In this problem, we have that:

g(x) = \log_{5}{x}

So f(x) = x, f'(x) = 1, a = 5

The derivative is

g'(x) = \frac{f'(x)}{f(x)*\ln{a}}

g'(x) = \frac{1}{x*\ln{5}}

g'(x) = \frac{1}{1.6094x}

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Can someone explain how to convert 70kg to lbs? i need to show work on my test.
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Answer:

70 kg is 154.3 lbs.

Step-by-step explanation:

There is 0.453592 kilograms per pound. That is just the conversion rate.

To find how many lbs 70 kg is, we do 70/0.453592 which is 154.3236.

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Which of the following groups are subsrts of rational numbers
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There has to be more to this question then i can help you 
5 0
4 years ago
Suppose A and B are dependent events. If P(A) = 0.5 and P(BIA) = 0.6, what is
klasskru [66]

If the probability of independent event A is 0.5, then P(A|B) will be 0.5. Then the correct option is B.

<h3>Which pair of events are called independent events?</h3>

When one event's occurrence or non-occurrence doesn't affect occurrence or non-occurrence of other event, then such events are called independent events.

Symbolically, we have:

Two events A and B are said to be independent iff we have:

P(A ∩ B) = P(A)P(B)

Comparing it with chain rule will give

P(A|B) = P(A)

P(B|A) = P(B)

Suppose A and B are dependent events.

If P(A) = 0.5

Then P(A|B) will be

P(A|B) = P(A)

P(A|B) = 0.5

Then the correct option is B.

Learn more about probability here:

brainly.com/question/1210781

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4 0
2 years ago
Based on historical data, your manager believes that 37% of the company's orders come from first-time customers. A random sample
fomenos

Answer:

0.6214 = 62.14% probability that the sample proportion is between 0.26 and 0.38

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

37% of the company's orders come from first-time customers.

This means that p = 0.37

A random sample of 225 orders will be used to estimate the proportion of first-time-customers.

This means that n = 225

Mean and standard deviation:

\mu = p = 0.37

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.37*0.63}{225}} = 0.0322

What is the probability that the sample proportion is between 0.26 and 0.38?

This is the pvalue of Z when X = 0.38 subtracted by the pvalue of Z when X = 0.26.

X = 0.38

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.38 - 0.37}{0.0322}

Z = 0.31

Z = 0.31 has a pvalue of 0.6217

X = 0.26

Z = \frac{X - \mu}{s}

Z = \frac{0.26 - 0.37}{0.0322}

Z = -3.42

Z = -3.42 has a pvalue of 0.0003

0.6217 - 0.0003 = 0.6214

0.6214 = 62.14% probability that the sample proportion is between 0.26 and 0.38

5 0
3 years ago
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