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katovenus [111]
3 years ago
8

Billy drove his car 290 miles in 5 hours. Sheila drove her car 132 miles in 2 hours. If each driver is traveling at a constant s

peed (in miles per hour), who is driving at a faster speed?​
Mathematics
1 answer:
Ksju [112]3 years ago
4 0

Answer:

Shelia is

Step-by-step explanation:

hope this helps plz mark brainlessly

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2.<br> Find the Area of the Shaded Region. (15 pts)<br> 2 m<br> 7 m<br> 12 m<br> 10 m
sweet [91]

Answer:

120 - 14 = 106

Step-by-step explanation:

7 x 2 = 14

10 x 12 = 120 therefore you,

120 - 14 = 106

3 0
3 years ago
Read 2 more answers
Anyone help me solve for y.
riadik2000 [5.3K]

Answer:

y = - 4

Step-by-step explanation:

Given

y = 2x + ( - 2) , that is

y = 2x - 2 ← substitute x = - 1

y = 2(- 1) - 2 = - 2 - 2 = - 4

This is confirmed by the point (- 1, - 4 ) on the graph

3 0
3 years ago
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Add 4x²y,-2xy²,-5xy²,3x²y plz explain​
Vinil7 [7]
4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2

This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4

To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)

If you multiply this as well you get the same answer I got with the addition
3 0
3 years ago
Which expression can be used to find the surface area of the following triangular prism? *picture of a triangular prism* Choose
KIM [24]

Answer:

A. 24+24+120+160+200

Step-by-step explanation:

Surface area of the triangular prism= addition of the area of each shape that forms the prism

There are two triangles

Area of a triangle=1/2*base*height

=1/2*8*6

=1/2*48

=24

Area of two triangles=24+24

There are 3 rectangles with different dimensions

Back rectangle=length×width

=20×6

=120

Bottom rectangle=length ×width

=20x8

=160

Top rectangle=length × width

=20×10

=200

Surface area =Area of two triangles + Back rectangle + Bottom rectangle + Top rectangle

=24+24+120+160+200

5 0
3 years ago
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g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and
allsm [11]

Answer:

Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, [ab]_K is equal to [ba]_K, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.

Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, [ab]_H = [ba]_H . Since a and b were generic elements of H, then H/G is abelian.

4 0
3 years ago
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