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Sonja [21]
4 years ago
12

What is the range of the relation? {(1, 2), (2, 4), (3, 2), (4, 6)}  A.{2, 4}  B.{1, 2, 3, 4, 6}  C.{2, 4, 6}  D.{1, 2, 3, 4}

Mathematics
1 answer:
tamaranim1 [39]4 years ago
5 0
(1)\ \ \ \ range:\ \ \ \{2, 4, 6\}\ \ \ \Rightarrow\ \ \ Ans.\ C\\\\(2)\ \ \ function:\ \ \ \{(1, 2); (2, 2); (3, 2); (4, 2)\}\ \ \ \Rightarrow\ \ \ Ans.\ D\\\\(3)\ \ \ f(4)=2-3\cdot4=2-12=-10\ \ \ \Rightarrow\ \ \ Ans.\ C\\\\(4)\ \ \ direct:\ \ \ y=ax\ \ \ \Rightarrow\ \ \ y= \frac{1}{3} x\ \ \ \Rightarrow\ \ \ Ans.\ B\\\\(5)\ \ \ f(x)=ax\ \ \ and\ \ \ f(4)=12\\.\ \ \ \ \ \Rightarrow\ \ \ 12=a\cdot4\ \ \ \Rightarrow\ \ \ a=3\ \ \ \Rightarrow\ \ \ f(x)=3x\ \ \ \Rightarrow\ \ \ Ans.\ (?)\\\\

(6)\ \ \ f(x)=ax^2\ \ \ and\ \ \ f(2)=48\\.\ \ \ \Rightarrow\ \ 48=a\cdot2^2\ \ \Rightarrow\ \ a=48:4=12\ \ \Rightarrow\ \ f(x)=12x^2\ \Rightarrow\ \ Ans.\ C\\\\(7)\ \ \ inversely:\ \ \ f(x)= \frac{a}{x} \ \ \ and\ \ \ f(2)=4\\.\ \ \ \Rightarrow\ \ \ 4= \frac{a}{2} \ \ \ \Rightarrow\ \ \ a=4\cdot2=8\ \ \ \Rightarrow\ \ \ y= \frac{8}{x}\ \ \ \Rightarrow\ \ \ Ans.\ B
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Step-by-step explanation:

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Step-by-step explanation:

General Concepts and Formulas:

Brackets

Parentheses

Exponents

Multiplication

Division
A
ddition
S
ubtraction

Steps:

1) Distribute

-12(32x-10y)

We must distribute the expression above by multiplying -12 by the coefficients and then adding the variables.

So first, multiple -12 by 32 and add the variable 'x' when getting the product:

-12(-384x - 10y)

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(-384x - 120y)

(Remove parenthesis)

⇒  -384x - 120y

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