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CaHeK987 [17]
3 years ago
8

What is the product? 4k+2/k^2-4*k-2/2k+1

Mathematics
1 answer:
VMariaS [17]3 years ago
7 0
\bf \cfrac{4k+2}{k^2-4}\cdot \cfrac{k-2}{2k+1}\implies \cfrac{2(2k+1)}{k^2-2^2}\cdot \cfrac{k-2}{2k+1}\implies \cfrac{2\underline{(2k+1)}}{\underline{(k-2)}(k+2)}\cdot \cfrac{\underline{k-2}}{\underline{2k+1}}
\\\\\\
\cfrac{2}{k+2}\cdot \cfrac{1}{1}\implies \cfrac{2}{k+2}
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