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3 years ago

What is an example of a risk management strategy

Chemistry

1 answer:

Nat2105 [25]3 years ago

8 0

Answer:

Risk management can be described as the identification and evaluation of certain risks beforehand and the appropriate steps that can be taken to avoid the problematic situations. Risk management is the forecasting of certain risks and the plans made to resist or overcome these risk situations.

An example of a risk management strategy can be a pet owner understanding that he'll have to make major payments for the health of the pet or will have to pay vet bills. In order to save money, the pet owner decided to go for pet insurance beforehand so that any problematic situation can be avoided.

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A small amount of a solid is added to water. The observation made after fifteen minutes is shown in the figure. Which of these s

natulia [17]

Answer:

B) sand

Explanation:

A) Oil is a wrong choice because it is a liquid not a solid and also if it is oil, it will float over the water surface as a droplets.

B) Sand is the right choice, because sand is a solid and it does not dissolve in water and stabilizes at the bottom.

C) Sugar is a wrong choice, because small amount of sugar will dissolve in water and be a homogeneous solution and does not appear as a particles.

D) Wood ships is also a wrong choice, even it is a solid and does not dissolve in water, but it will float over the water surface.

4 0

3 years ago

a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re

Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

Given : 59.4 g of $H_2SO_4$ in 100 g of solution

moles of $H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61$

Volume of solution = $\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.61\times 1000}{54.6ml}=11.2M$

To calculate the volume of acid, we use the equation given by neutralisation reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock acid which is $H_2SO_4$

$M_2\text{ and }V_2$ are the molarity and volume of dilute acid which is $H_2SO_4$

We are given:

$M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL$

Putting values in above equation, we get:

$11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL$

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0

3 years ago

Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.

insens350 [35]

Given:
Iron, 125 grams T
1 = 23.5 degrees Celsius, T2 = 78 degrees Celsius.

Required:
Heat produced in kilojoules

Solution:
The molar mass of iron is 55.8 grams per mole. SO we need to change the given mass of iron into moles.

Number of moles of iron = 125 g/(55.8 g/mol) = 2.24 moles

Q (heat) = nRT = nR(T2 = T1)
Q (heat) = 2.24 moles (8.314 Joules per mol degrees Celsius) (78.0 degrees Celsius – 23.5 degrees Celsius)
Q (heat) = 1014.97 Joules or 1.015 kilojoules This is the amount of heat produced in warming 125 g f iron.

7 0

3 years ago

The maximum number of trees that can be grown in an area and have all of the resources they need to survive is the forest's ____

alisha [4.7K]

Answer:

growth limit for trees

Explanation:

the awnser is the growth limit for trees

6 0

2 years ago

Read 2 more answers

Long ago, living things were divided into two main groups: _________

solmaris [256]

Answer:

I think the answer is Prokaryote and Eukaryote

Explanation:

6 0

3 years ago