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qwelly [4]
3 years ago
14

A balloon that contains 0.750 moles of gas has a volume of 16.8 l. if the balloon expands to a volume of 25.4 l at a constant pr

essure and temperature, how many moles of gas would the balloon contain? 0.496 mol 0.882 mol 1.13 mol 6.45 mol
Chemistry
2 answers:
fomenos3 years ago
6 0

The answer is 1.13 mol

Rainbow [258]3 years ago
3 0

Answer: 1.13 mol

Explanation:

Avogadro's Law: This law states that volume is directly proportional to the number of moles of the gas at constant pressure and temperature.

V\propto n   (At constant temperature and pressure)  

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1 = initial volume of gas = 16.8 L

V_2 = final volume of gas = 25.4 L

n_1 = initial number of moles = 0.750

n_2 = final number of moles = ?

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{16.8}{0.750}=\frac{25.4}{n_2}

n_2=1.13

Therefore, the final moles will be 1.13.

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What is the parent isotope when Cl-33 is formed during a beta decay?
zzz [600]

Answer:

33/16 S

Explanation:

In beta decay, the atomic number of the daughter nucleus increases by one unit while the mass of the daughter nucleus remains the same as that of the parent nucleus.

Hence, if we know that a beta decay has occurred, then the parent nucleus must have the same mass as its daughter nucleus but have an atomic number that is less than that of the daughter nucleus by only one unit, hence the answer above.

7 0
3 years ago
How could you dissolve more solid in a saturated solution in a liquid solvent? explain please
storchak [24]
There are 3 ways,
1) Increase the temperature of the solvent- The higher the temperature of the solvent, the faster we can expect the solute to dissolve

2 )Increase the rate of stirring- The faster the rate at which we stir the mixture, the faster we can expect the solute to dissolve

3) Decrease the size of the solute particles- The smaller the size of the particles, the faster we can expect the solute to dissolve in the. This is because small particles have a larger surface area that come into contact with the solvent

Hope this helps :)
4 0
3 years ago
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 28.0 mL of H
e-lub [12.9K]

A) Initial moles of NH3 = 75/1000 x 0.200 = 0.015 mol

Moles of HNO3 added = 28/1000 x 0.500 = 0.014 mol

NH3 + HNO3 => NH4+ + NO3-

Moles of NH3 left = 0.015 - 0.014 = 0.001 mol

Moles of NH4+ = 0.014 mol

Ka(NH4+) = Kw/Kb(NH3)

= 10-14/1.8 x 10-5 = 5.556 x 10-10

Henderson-Hasselbalch equation:

pH = pKa + log([NH3]/[NH4+])

= -log Ka + log(moles of NH3/moles of NH4+) since volume is the same for both

= -log(5.556 x 10-10) + log(0.0065/0.014)

= 8.14

7 0
3 years ago
Read 2 more answers
Concept of mole chemistry question<br><br><br><br>​
vredina [299]

Answer:

How many molecules of water are there in 54 g of H2O H 2 O ? Solution. Molar Mass of H2O H 2 O = 2 + 16 = 18 g/moles. So ,number of moles of H2O H 2 O = Mass/Molar Mass = 54/18 =3 moles. Now 1 moles = 6.022×1023 6.022 × 10 23 molecule.

5 0
2 years ago
3)
damaskus [11]

Answer:

your answer is C

Explanation:

The electron-dot structure of NH3 places one set of nonbonding electrons in the valence shell of the nitrogen atom. that means there are three bonded atoms and one single pair for a coordination number of four surrounding  the nitrogen, the same occurs in water to. along with the Lewis dot structure for ammonia, NH3. the non bonding atoms are basically like hydrogen atoms the try to refuse to bond and they can't be fused unless the right conditions are met.

4 0
2 years ago
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