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qwelly [4]
3 years ago
14

A balloon that contains 0.750 moles of gas has a volume of 16.8 l. if the balloon expands to a volume of 25.4 l at a constant pr

essure and temperature, how many moles of gas would the balloon contain? 0.496 mol 0.882 mol 1.13 mol 6.45 mol
Chemistry
2 answers:
fomenos3 years ago
6 0

The answer is 1.13 mol

Rainbow [258]3 years ago
3 0

Answer: 1.13 mol

Explanation:

Avogadro's Law: This law states that volume is directly proportional to the number of moles of the gas at constant pressure and temperature.

V\propto n   (At constant temperature and pressure)  

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1 = initial volume of gas = 16.8 L

V_2 = final volume of gas = 25.4 L

n_1 = initial number of moles = 0.750

n_2 = final number of moles = ?

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{16.8}{0.750}=\frac{25.4}{n_2}

n_2=1.13

Therefore, the final moles will be 1.13.

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3 years ago
For the chemical reaction:
Kamila [148]

Answer:

Volume of ammonia produced = 398.7 dm³

Explanation:

Given data:

Volume of N₂ = 200 dm³

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Solution:

Chemical equation:

N₂ + 3H₂     →      2NH₃

Number of moles of N₂:

PV = nRT

1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K

n = 200 atm.L /22.41 atm.L/mol

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Now we will compare the moles of ammonia and nitrogen.

               N₂          :         NH₃

                1            :           2

              8.9          :        2/1×8.9 = 17.8 mol

Volume of ammonia:

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7 0
3 years ago
2. How many nanoliters are in 2.87 x 10-10 gallons?
Morgarella [4.7K]

Answer:

1.09nL

Explanation:

Hello,

In this case, given that 1 gal equals 4 qt, 1 qt equals 0.9464 L and 1 L equals 1x10⁹ nL, the dimensional analysis turns out:

2.87x10^{-10}gal*\frac{4qt}{1gal} *\frac{0.9464L}{1qt}*\frac{1x10^9nL}{1L}\\  \\1.09nL

Best regards.

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