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qwelly [4]
3 years ago
14

A balloon that contains 0.750 moles of gas has a volume of 16.8 l. if the balloon expands to a volume of 25.4 l at a constant pr

essure and temperature, how many moles of gas would the balloon contain? 0.496 mol 0.882 mol 1.13 mol 6.45 mol
Chemistry
2 answers:
fomenos3 years ago
6 0

The answer is 1.13 mol

Rainbow [258]3 years ago
3 0

Answer: 1.13 mol

Explanation:

Avogadro's Law: This law states that volume is directly proportional to the number of moles of the gas at constant pressure and temperature.

V\propto n   (At constant temperature and pressure)  

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1 = initial volume of gas = 16.8 L

V_2 = final volume of gas = 25.4 L

n_1 = initial number of moles = 0.750

n_2 = final number of moles = ?

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{16.8}{0.750}=\frac{25.4}{n_2}

n_2=1.13

Therefore, the final moles will be 1.13.

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Look at the picture of two different substances above. Which substance is a mixture? A. Y and Z
Feliz [49]

Answer:

option B is correct.

Y is a mixture in the picture.

Explanation:

Different types of substances combine physically and form a mixture.  

Mixture formed by the combination of two or more substances that that combine in same physical state.

For example mixture of copper sulphate and solid chloride in dry form and that will look like white and blue crystal in a mixture.

The picture Z showing dots of same color and is not a mixture, while picture Y shows dots of different colors clearly indicating that it is picture for mixture.

5 0
3 years ago
Read 2 more answers
he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c
Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

<u>Answer:</u> The rate constant at 324°C is 61.29M^{-1}s^{-1}

<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{244^oC} = equilibrium constant at 244°C = 6.7M^{-1}s^{-1}

K_{324^oC} = equilibrium constant at 324°C = ?

E_a = Activation energy = 71.0 kJ/mol = 71000 J/mol   (Conversion factor:  1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 244^oC=[273+244]K=517K

T_2 = final temperature = 324^oC=[273+324]K=597K

Putting values in above equation, we get:

\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}

Hence, the rate constant at 324°C is 61.29M^{-1}s^{-1}

8 0
3 years ago
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Natasha2012 [34]
I think the answer is 7mm but I'm not sure.

Have a great day!
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Answer:

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Express the following in regular notation:
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A because if you multiple it, you will be moving the decimal one time
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