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sergeinik [125]
1 year ago
12

The chemical elements display periodicity when they're arranged according toQuestion 10 options:A) atomic mass.B) atomic volume.

C) atomic number.D) atomic weight.
Chemistry
1 answer:
BartSMP [9]1 year ago
5 0

The periodic table is an ordered way of representing chemical elements. They were ordered according to their atomic number, remember that the atomic number corresponds to the number of protons of the elements.

So the answer will be option C) Atomic Number

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N-Alkylbenzene-sulphonamide. Here what is "N"?
zlopas [31]

Answer:

N = Nitrogenous base

Explanation:

Hope it helps

4 0
2 years ago
The reactant concentration in a first-order reaction was 8.10×10−2 M M after 15.0 s s and 1.80×10−3 M M after 90.0 s s . What is
kipiarov [429]

Answer:

The answer to the question is

The rate constant for the reaction is 1.056×10⁻³ M/s

Explanation:

To solve the question, e note that

For a zero order reaction, the rate law is given by

[A] = -k×t + [A]₀

This can be represented by the linear equation y = mx + c

Such that y = [A], m which is the gradient is = -k, and the intercept c = [A]₀

Therefore the rate constant k which is the gradient is given by

Gradient = \frac{[A]_{2} - [A]_{1}  }{t_{2} - t_{1}  }  where [A]₁ = 8.10×10⁻² M and [A]₂ = 1.80×10⁻³ M

= \frac{1.80*10^{-3} M- 8.10*10^{-2} M}{90 s - 15 s} = -0.001056 M/s = -1.056×10⁻³ M/s

Threfore k = 1.056×10⁻³ M/s

3 0
3 years ago
What is formed when atoms join together with a covalent bond?
Feliz [49]

B) a molecule

A molecule is formed when two atoms join together with a covalent bond.

5 0
3 years ago
Read 2 more answers
Calculate the missing variables in each experiment below using Avogadro’s law.
blagie [28]

Answer:

The answer to your question is: letter c

Explanation:

Data

V1 = 612 ml    n1 = 9.11 mol

V2 = 123 ml    n2 = ?

Formula

                               \frac{V1}{n1}  =  \frac{V2}{n2}

                                         n2 = \frac{n1V2}{V1}

                                         n2 = \frac{(9.11)((123)}{(612)}

                                                n2 = 1.83 mol                                                

5 0
3 years ago
What is the volume, in mL, of 0.50 moles of ammonia (NH3) at STP?
blagie [28]
For the purpose we will here use the ideal gas law:

p×V=n×R×T

V= ?
n = 0.5 moleT= 273.15 K (at STP)
p= 101.325 kPa (at STP)
R is  universal gas constant, and its value is 8.314 J/mol×K

Now when we have all necessary date we can calculate the number of moles:
V=nxRxT/p
V=0.5x8.314x273.15/101.325= 11.2 L = 11200 mL

Answer: D.
5 0
3 years ago
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