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lapo4ka [179]
3 years ago
9

A 7.26kg bowling ball (16 pounds) is at rest what is the net force on the bowling ball

Physics
1 answer:
cestrela7 [59]3 years ago
5 0
Well since the bowling ball is at rest and is not moving at all, and assuming that the ball is on an even surface, the Fg is equal to the FN = normal force, and thus all forces are balanced, the Fnet = 0.
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When Mendeleev organized elements in his periodic table in order of increasing mass, similar elements with similar properties we
Temka [501]
Similar elements with similar properties were in the same groups and periods for instance lithium(Li) and sodium(Na) are alkaline metals and so belong to the same group (that is group 1).Also Hydrogen(H) and Helium(He) both have only one shell or energy level and so belong to the same period.
8 0
3 years ago
Which observation did researchers make in studies on separated twins ?
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Depending on whether they where conjoined initially, or where born separately really changes the answer of this question. Although studies show that twins generally have a kinetic link, more practical research says that twins are 25% more likely to both be left handed, which is a recessive gene, they are also more likely to die in child birth, twins are more likely to understand and be biligual, along with many other advantages twins may have.
7 0
3 years ago
A 1,155 kg truck has a velocity of 18 m/s. What is the momentum of the truck?
77julia77 [94]

The momentum of truck is 20790 kg m/s

<em><u>Solution:</u></em>

Given that we have to find the momentum of truck

From given, 1155 kg truck has a velocity of 18 m/s

Therefore,

Mass = 1155 kg

Velocity = 18 m/s

<em><u>The momentum is given by formula:</u></em>

p = m \times v

Where, m is mass in kg and v is velocity in m/s

Substituting the values we get,

p = 1155 \times 18\\\\p = 20790

Thus momentum of truck is 20790 kg m/s

8 0
3 years ago
Describe in brief the importance of measurement in our daily life?<br>​
Volgvan

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6 0
3 years ago
A horizontal force of 25 N is required to push a wagon across a sidewalk at a constant speed.
lions [1.4K]

Answer:

a. The net force acting on the wagon is zero

b. The value of the force of friction is 25 N

c. The effect would be is the frictional force must be increase

Explanation:

Lets explain how to solve the problem

A horizontal force of 25 N is required to push a wagon across a sidewalk

at a constant speed

a.

→ Constant speed means acceleration is zero

→ Force = mass × acceleration

→ Force = mass × 0

→ Force = 0

<em>The net force acting on the wagon is zero</em>

b.

The wagon moves with constant speed, then

→ ∑ force = 0

There are two forces acting on the wagon external force of 25 N,

and the frictional force which is opposite to the direction of motion

→ 25 - Frictional force = 0

→ Frictional force = 25 N

<em>The value of the force of friction is 25 N</em>

c.

The force increased to 30 N

If the wagon still moves with constant speed

Due to Newton's law ∑ force in the direction of motion = mass ×

acceleration, but acceleration is 0 because the wagon moves with

constant speed, then ∑ F = 0

So the frictional force must increase to 30 N

<em>The effect would be is the frictional force must be increase</em>

<em></em>

<em>If the frictional force does not increase the wagon will accelerate</em>

6 0
3 years ago
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