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Alex Ar [27]
2 years ago
8

Why do different substances have different melting and boiling points?

Physics
1 answer:
azamat2 years ago
3 0
Because the atoms and molecules all have different properties
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<span>The bullfrog is sitting at rest on the log. The force of gravity pulls down on the bullfrog. We can find the weight of the bullfrog due to the force of gravity. weight = mg = (0.59 kg) x (9.80 m/s^2) weight = 5.782 N The bullfrog is pressing down on the log with a force of 5.782 newtons. Newton's third law tells us that the log must be pushing up on the bullfrog with a force of the same magnitude. Therefore, the normal force of the log on the bullfrog is 5.782 N</span>
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Suppose that a white dwarf is gaining mass through accretion in a binary system. what happens if the mass someday reaches the 1.
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What type of lever has the fulcrum between the resistance arm and the effort arm?
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You are listening to the radio when one of your favorite songs comes on, so you turn up the volume. If you managed to increase t
andrew-mc [135]

To solve this problem we need to apply the corresponding sound intensity measured from the logarithmic scale. Since in the range of intensities that the human ear can detect without pain there are large differences in the number of figures used on a linear scale, it is usual to use a logarithmic scale. The unit most used in the logarithmic scale is the decibel yes described as

\beta_{dB} = 10log_{10} \frac{I}{I_0}

Where,

I = Acoustic intensity in linear scale

I_0 = Hearing threshold

The value in decibels is 17dB, then

17dB = 10log_{10} \frac{I}{I_0}

Using properties of logarithms we have,

\frac{17}{10} = log_{10} \frac{I}{I_0}

log_{10} \frac{I}{I_0} = 1.7

\frac{I}{I_0} = 10^{1.7}

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Therefore the factor that the intensity of the sound was 50.12W/m^2

5 0
3 years ago
A piano emits frequencies the range from a low of about 28 Hz to a high of about 4200 Hz. Find the range of wavelengths in air a
Step2247 [10]
V=wave velocity , <span>f= frequency, </span><span>λ=wavelength </span>
<span>Use it to find corresponding wavelengths for</span><span> f=28 Hz </span>
<span>λ= v/f= 337/28=12.036 m 
</span>
<span>for f=4200 Hz </span>
<span>λ= v/f=337/4200= 0.08 m </span>
<span>So max. wavelength is 12.036 m and </span>
<span>Min Wavelength is 0.08 m </span>
<span>So the range is between .08 m and 12.036 m
</span>Hope this helps. 
4 0
3 years ago
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