34 = 4(-3 - 6x + x what is the solution

1. One half of 1% converted to a decimal is . 2. 0.184 rounded to the hundredths place is . 3. The first three place values to t

solmaris [256]

Answer:

.Yes 4.

1. One half of 1%

1% is the same as 1/100

= 0.01

Half of it means (1/2 of if)

= (1/2)×0.01

= 0.005

2.O.184 rounded to hundredth place

hundredth place is two decimal places behind the decimal point

A third decimal point, we have 4 which cannot be rounded up

Therefore number upto hundredth place shall be

0.18

3. Yes,

The first place to the right of decimal point is called tenth place

Similarly second point to the right of decimal point is called hundrdth place

Third place is thousandth place

4. 3/25 = 3×10/25×10 =6/50 =0.12

5 0.45= 45/100 5 goes in 45 9 times and 5 goes in 100, 20times= 9/20

6.$39,918.23 to nearest thousands is $39,000

7.5% is the same as 5/100 =1/20

8. 0.04 to percentage means

0.04 × 100= 4%

9.0.727935 converted to nearest thousands is 0.7279

10.325/790 converted to fraction is 0.4113

To nearest hundreds is 0.411

7 0

3 years ago

Solve for x. Show steps. 1. 3x = 2x + 2 2. 3x + 5 = 4x + 1 3. 6x + 3 = 3x + 12

nignag [31]

Step-by-step explanation:

3x = 2x + 2

3x - 2x = 2

x = 2

2. 3x + 5 = 4x + 1

4x - 3x = 5 - 1

x = 4

3. 6x + 3 = 3x + 12

6x - 3x = 12 - 3

3x = 9

x = 3

3 0

3 years ago

If you roll two fair six-sided dice, what is the probability that at least one die shows 3?

tiny-mole [99]

Answer:

P(3) = 1/12

Step-by-step explanation:

12 is the denominator because you have two die with six sides.

5 0

3 years ago

Read 2 more answers

Which expression is a sum of cubes?

erik [133]

we know that

A polynomial in the form $a^{3} +b^{3}$ is called a sum of cubes

so

Let's verify each case to determine the solution

case A) $-64x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-64=-4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case A) is not a sum of cubes

case B) $-32x^{6} y^{12} +125x^{16} y^{3}$

we know that

$-32=-2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{16}=x^{15} *x=x*(x^{5})^{3}$ -------> is not a perfect cube

$y^{3}= (y)^{3}$

therefore

the case B) is not a sum of cubes

case C) $32x^{6} y^{12} +125x^{9} y^{3}$

we know that

$32=2^{5}$ -------> is not a perfect cube

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

therefore

the case C) is not a sum of cubes

case A) $64x^{6} y^{12} +125x^{9} y^{3}$

we know that

$64=4^{3}$

$x^{6}= (x^{2})^{3}$

$y^{12}= (y^{4})^{3}$

$125=5^{3}$

$x^{9}=(x^{3})^{3}$

$y^{3}= (y)^{3}$

Substitute

$4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}$

$(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}$

therefore

the answer is

$64x^{6} y^{12} +125x^{9} y^{3}$ is a sum of cubes

6 0

3 years ago

Read 2 more answers

Help Fast I’m Struggling In Picture

Brilliant_brown [7]

Answer:

4/5

Step-by-step explanation:

sohcahtoa meaning sin is opposite over hypotenuse

8 0

3 years ago

34 = 4(-3 - 6x + xwhat is the solution​

34 = 4(-3 - 6x + xwhat is the solution