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RSB [31]
3 years ago
15

A given mass of oxygen at room temperature occupies a volume of 500.0 ml at 1.50 atm pressure. what pressure must be applied to

compress the gas to a volume of only 150.0 ml? answer
Chemistry
1 answer:
givi [52]3 years ago
8 0
Boyle's law gives the relationship between pressure of a gas and volume.
It states that the pressure of a gas is inversely proportional to volume of gas at a constant temperature.
PV = k
where P - pressure , V - volume and k - constant 
P1V1 = P2V2 
where parameters for the first instance are on the left side of the equation and parameters for the second instance are on the right side of the equation.
1.50 atm x 500.0 mL = P x 150.0 mL 
P = 5 atm
applied pressure should be 5 atm to compress the gas.
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2 years ago
Avogadro's law states that the _____ of a gas is directly proportional to the _____ of the gas when _____ stay the same
attashe74 [19]

Answer:

The three blanks for this answer, are

1. volumen

2. moles

3. Temperature and pressure.

So, Avogadro's law states that the volume of a gas is directly proportional to the moles of the gas when temperature and pressure stay the same

Explanation:

Imagine you have 10 moles of a gas which is contained in 50 L. How many moles of that gas, you will have if the volumen has been reduced to 10 L. (Of course, don't forget that T° and pressure are the same)

There is an equation like this, initial moles /initial volume = moles at the end/volume at the end, (Avogadro law for gases), so 10/50 =moles at the end/10.  When u operate, moles at the end = (10 x 10) / 50.

Moles at the end are 2. Did u get it?. Volumen has been reduced, also the moles.

7 0
3 years ago
The majority of water molecules moving across plasma membranes by osmosis do so via a process that is most similar to ____.
ValentinkaMS [17]

Answer:

The answer is Facilitated Diffusion

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Osmosis is most similar to facilitated diffusion.

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4 0
3 years ago
Calculate the number of miles of magnesium,chlorine, and oxygen atoms in 5.00 moles of magnesium perchlorate
Zigmanuir [339]

Answer:

5.00 mol Mg

10.0 mol Cl

40.0 mol O

Explanation:

Step 1: Given data

Moles of Mg(ClO₄)₂: 5.00 mol

Step 2: Calculate the number of moles of Mg

The molar ratio of Mg(ClO₄)₂ to Mg is 1:1.

5.00 mol Mg(ClO₄)₂ × 1 mol Mg/1 mol Mg(ClO₄)₂ = 5.00 mol Mg

Step 3: Calculate the number of moles of Cl

The molar ratio of Mg(ClO₄)₂ to Cl is 1:2.

5.00 mol Mg(ClO₄)₂ × 2 mol Cl/1 mol Mg(ClO₄)₂ = 10.0 mol Cl

Step 4: Calculate the number of moles of O

The molar ratio of Mg(ClO₄)₂ to Cl is 1:8.

5.00 mol Mg(ClO₄)₂ × 8 mol O/1 mol Mg(ClO₄)₂ = 40.0 mol O

4 0
3 years ago
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