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4 years ago

The product of 5 and the difference of 1 and a number.

Mathematics

1 answer:

Molodets [167]4 years ago

7 0

Answer:

Simplify.

There's a product, so we are multiplying.

5 x...

The difference of one and a number. The number is a variable, since it could be any number.

1 - x

Let's combine them.

5 x (1 - x)

5(1 - x)

Hope this helped!

Mark this Brainliest, not that it matters.

Good luck :)

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(2a^2b + 3ab^2 - b^3) - (4b^3 - 3ab^2 -6a^2b)

skelet666 [1.2K]

Hi there!

~

$(2a^2b+3ab^2-b^3)-(4b^3-3ab^2-6a^2b)$

Distribute the Negative Sign:

$= 2a^2 b + 3ab^2 - b^3 + -1(4b^3 - 3ab^2 - 6a^2b)\\= 2a^2 b + 3ab^2 + - b^3 + -1 (4b^3) + -1 (-3ab^2) + -1 (-6a^2b)\\= 2a^2 b + 3ab^2 + -b^3 + -4b^3 + 3ab^2 + 6a^2 b$

Combine Like Terms:

$= 2a^2 b + 3ab^2 - b^3 + -4ab^3 + 3ab^2 + 6a^2 b\\= (2a^2 b + 6a^2 b) + ( 3ab^2 + 3ab^2) + (-b^3 + -4b^3) \\= 8a^2 b + 6ab^2 + -5b^3$

Answer : $8a^2 b + 6ab^2 + -5b^3$

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