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andriy [413]
4 years ago
5

Will someone please help me as soon as possible please please please

Physics
1 answer:
marin [14]4 years ago
4 0
19).  Nuclear energy
20).  physical world.
21).  A physical description
22).  exact measurement
23).  the range of a set
24).  you divide by
25).  are variables.
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How far will a runner travel at an average speed of 5m/s for 20 minutes?
Sonja [21]
Multiply the speed and time to get your answer of how far the runner travels
6 0
3 years ago
A box of books weighing 305 N is shoved
Anna [14]

Answer:

3.1 s

Explanation:

from the question we are given the the following:

Weight of books (Fb) = 305 N

Push force (Fp) = 516 N

distance (s) = 5.82 m

Angle of force exerted = 32 degrees

acceleration due to gravity (g) = 9.81 m/s^{2}

coefficient of friction Uk= 0.59

time (t) = ?

mass of the book (m) = weight / (g) =  305 / 9.8 = 31 kg

lets first get the net force from the summation of vertical forces

Fnet = Fpush + Fgravity

F net = 516 + 305sin32

F net = 677.6 N

now lets get the acceleration from the summation of the horizontal forces

Fpcos32 - friction force = m x a

Fpcos32 - (Uk x F net) = m x a

516cos32 - (0.59 x 677.6) = 31 x a

37.8 = 31a

a =  1.22m/s^{2}

now that we have our acceleration we can get the time from the equation of motion

s = ut + o.5at^{2}

u ( initial velocity ) = 0 because the box was initially at rest

5.82 = (0 x t ) + (0.5 x 1.22 x t^{2})

5.82 = 0.61t^{2}

t = 3.1 s

5 0
3 years ago
An ideal gas at 0∘C consists of 1.0×1023 atoms. 20 J of thermal energy are added to the gas. Part A What is the new temperature
fomenos

Answer: New temperature T2 = 9.66°C

Explanation:

Given;

Energy added ∆E = 20J

Initial temperature T1 = 0°C

Number of atom = 1.0×10^23

Using the energy equation.

∆E = (3/2)nR∆T

∆T = (2/3)∆E/nR

Where ;

R = universal gas constant = 8.314J/mol-K

n = number of moles = N/Nt

Nt = number of atoms in one mole of gas = 6.022×10^23

n = 1.0 ×10^23/6.022×10^23= 0.166

∆T = (2/3)×20/(0.166×8.314)

∆T = 9.66

T2 = T1+∆T = 0 + 9.66

T2 = 9.66°C

4 0
3 years ago
Two charge spears are 20 cm apart and extract an attractive force of 8x10^-9 N on each other. Which will be the force of attract
Talja [164]

Answer:

3.2 × 10⁻⁸ N.

Explanation:

By Coulomb's Law, the magnitude of the electromagnetic force between two point charges is inversely proportional to the square of their separation, r. In other words,

\displaystyle \frac{F_1}{F_2} = {\left(\frac{r_2}{r_1}\right)}^{2}.

  • Initial electromagnetic force F_1 = 8\times 10^{-9}\;\text{N};
  • Initial Separation r_1 = 20\;\text{cm};
  • Final Separation r_2 = 10\;\text{cm}.

Final electromagnetic force:

\displaystyle F_2 = F_1 \cdot \left(\frac{r_2}{r_1}\right)^{2} = 8\times 10^{-9}\times \left( \frac{20}{10}\right)^{2} = 3.2\times 10^{-8}\;\text{N}.

4 0
4 years ago
An equilibrium is not changed by a change in pressure.<br> a. True<br> b. False
alexandr1967 [171]
An equilibruium is not changed by a changed in pressure. the answer is false
7 0
3 years ago
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