Answer:
2.28 cm
Explanation:
Radius of the proton if v and B is perpendicular will be,
Now,
mass of proton, .
Radius of the orbit, .
Magnetic field, .
Charge on the proton, .
Now substitute all the variables in r.
.
.
Therefore the radius of the orbit of moving proton is 2.28 cm.
Answer: The magnetic field is 4×10^-4T
Explanation:
Using the magnetic field equation
B=μI/2πr
B= magnetic field =?
l= current in the wire=2.0A
r= distance from the axis of wire=1.0mm= 0.001m
μ=magnetic permeability =4π×10^-7N/m
B= (4π×10^-7 × 2.0)/(2π × 0.001)
B= 4×10^-4T
Therefore the magnetic field is 4×10^-4T
Answer:
x=?
dt=?
vi=23m/s
vf=0m/s (it stops)
d=0.25m/s^2
time =
vf=vi+d: 0=23m/s+(0.25m/s^2)t
t=92s
displacement=
vf^2=vi^2+2a(dx)
23^2=0^2+2(0.25m/s^2)x =-1058m
Explanation:
you can find time from vf = vi + a(Dt): 0 = 23 m/s + (0.25 m/s/s)t so t = 92 s and you can find the displacement from vf2 = vi2 + 2a(Dx) and find the answer in one step: 232 = 02 + 2(0.25 m/s/s)x so x = -1058 m
Answer:Colloids include gels and emulsions; the particles do not settle, and cannot be separated out by ordinary filtering or centrifugtion
Explanation:they are homogenous/non crystalline
Answer:
Displacement...
Explanation:
Displacement is a vector quantity as it have both magnitude and direction...